1-100之间的偶数之和

Question

我发现没有代码使用for循环来解决此问题。我的问题似乎是数字的加法

total = 0 #defined total
for number in range(1,101): #set a for loop with a range between (1-101)
    if number %2 == 0:  #if number(1-101) is divisible by 2 == 0
        total = sum(int(number)) #TypeError: 'int' object is not iterable
        print(total) # expected result is to print 2550

Answer 1

您可以使用python内置函数sum。

sum(range(0, 101, 2))