Question

我使用SUM（CASE WHEN）来计算Yes和No的数量，它工作正常。

我有问题从两张桌子计算匹配的手机号码的数量。它似乎没有正确计数。

乳制品表中有MobileNO字段，销售表中有mobile字段

SELECT 
       D.Username, 
       SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes, 
       SUM(CASE WHEN D.type = 'No' THEN 1 ELSE 0 END) as No, 
       SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other, 
       (SELECT SUM(CASE WHEN D.MobileNo = S.mobile THEN 1 ELSE 0 END) from sales as S) as Sales, 
       COUNT(*) as TOTAL FROM dairy as D 
WHERE source = 'Company' AND UNIX_TIMESTAMP(CheckDate) >= 1293840000 AND UNIX_TIMESTAMP(CheckDate) <= 1322697600 
group by D.Username order by TOTAL DESC

Answer 1

SELECT 
       D.Username, 
       SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes, 
       SUM(CASE WHEN D.type = 'No' THEN 1 ELSE 0 END) as No, 
       SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other, 
       SUM(CASE WHEN S.mobile IS NULL THEN 0 ELSE 1 END) as Sales, 
       COUNT(*) as TOTAL 
FROM dairy as D 
LEFT JOIN (SELECT DISTINCT mobile FROM sales) as S ON D.MobileNo = S.mobile
WHERE source = 'Company' AND UNIX_TIMESTAMP(CheckDate) >= 1293840000 AND UNIX_TIMESTAMP(CheckDate) <= 1322697600 
group by D.Username order by TOTAL DESC

计算两个表的销售数量

1 个答案: