在本地反应中关闭父组件时，有没有一种方法不关闭键盘

Question

我当前要在父组件或模态可见时自动打开键盘，这是我想要的，但是问题是，当我先关闭模态时，键盘将被关闭，然后模态将被关闭。被解雇，这会导致不良的UI交互性。我想保持键盘静止不动，只关闭父组件或模态，而不是两者。当KeyboardShouldPersistTapsis设置为“ always”时，我在KeyboardAvoidingView中使用了scrollView。您可以在下面找到我的代码：

    const amountInput = () => (
    <View style={styles.inputAndTextContainer}>
      <Text style={styles.textStyle}>ETB</Text>
      <TextInput
        onKeyPress={({ nativeEvent }) => {
          return nativeEvent.key === 'Backspace' ? clearLastChar() : null;
        }}
        caretHidden
        ref={textInputRef}
        style={styles.inputStyle}
        autoCapitalize="none"
        autoCorrect={false}
        keyboardType="numeric"
        defaultValue={amount.value}
        /* value={amount.value} */
        autoFocus
        maxLength={6}
        onChangeText={num => {
          setAmount({ value: addCommaToNumber(num) });
        }}
      />
    </View>
  );

   return (
    <View>
      <Modal
        isVisible={isVisible}
        animationIn="bounceInUp"
        animationOut="slideOutDown"
        animationOutTiming={200}
        animationInTiming={200}
        style={{ margin: 0 }}
      >
        <KeyboardAvoidingView behavior="padding">
          <Header />
          <ScrollView
            keyboardShouldPersistTaps="always"
            alwaysBounceVertical={false}
          >
            {amountInput()}
            {state && state.length ? someFunc() : anotherFunc()}
          </ScrollView>

          {renderModal()}
          {state ? someFunc() : someotherfunc()}
        </KeyboardAvoidingView>
      </Modal>
    </View>
    )