Question

我有一个字典列表，需要将其解析为字典{A：[b，c]}。

iam_profile_association = [{'AssociationId': 'iip-assoc-08c2998aabf8ad37e', 'InstanceId': 'i-078cf2f285a2bb4d3', 'IamInstanceProfile': {'Arn': 'arn:aws:iam:::instance-profile/STANDARD-SSM-INSTANCEPROFILE-us-east-1', 'Id': 'AIPAZTOKUMIFDJ4VGT2FP'}, 'State': 'associated'}, {'AssociationId': 'iip-assoc-0afc8368072fa1d7e', 'InstanceId': 'i-076d4c961d800ba18', 'IamInstanceProfile': {'Arn': 'arn:aws:iam:::instance-profile/STANDARD-SSM-INSTANCEPROFILE-us-east-1', 'Id': 'AIPAZTOKUMIFDJ4VGT2FP'}, 'State': 'associated'}, {'AssociationId': 'iip-assoc-0c46d1f23de061e98', 'InstanceId': 'i-0942731f00ebd33e1', 'IamInstanceProfile': {'Arn': 'arn:aws:iam:::instance-profile/STANDARD-SSM-INSTANCEPROFILE-us-east-1', 'Id': 'AIPAZTOKUMIFDJ4VGT2FP'}, 'State': 'associated'}]

                    iam_dict = {}
                    for iam_assoc in iam_profile_association:
                        
                        iam_dict[iam_assoc['InstanceId']] = [iam_assoc['AssociationId'],iam_assoc['IamInstanceProfile']['Arn']]
                        
                        print (iam_dict)

iam_dict仅显示第一个值：

{'i-078cf2f285a2bb4d3': ['iip-assoc-08c2998aabf8ad37e', 'arn:aws:iam::660239311370:instance-profile/STANDARD-SSM-INSTANCEPROFILE-us-east-1']}

有人可以帮我吗？我想以dict格式存储所有值。

Answer 1

您的print在for循环中，将其移到外部（在其中输入标签）

iam_dict = {}
for iam_assoc in iam_profile_association:

    iam_dict[iam_assoc['InstanceId']] = ...........
                        
print (iam_dict)

要比从您的要求中得出更多的结果是很棘手的。但这将是一个好的开始。

字典解析的Python列表

1 个答案: