我有一个类似上面的链接的Google表格,看起来像这样
Timestamp Name
6/29/2020 23:32:42 aaaa
6/29/2020 23:32:50 aaaa
6/29/2020 23:32:54 aaaa
6/29/2020 23:33:00 bbbbb
6/29/2020 23:33:05 bbbbb
6/29/2020 23:33:10 bbbbb
6/29/2020 23:33:10 bbbbb
但是我需要获取/创建这样的输出
Name NumberOfItem
aaaa 3
bbbbb 4
如何在Google工作表上完成此操作
答案 0 :(得分:2)
尝试:
// Use a range so you directly clamp the value in the Inspector
[Range(1,30)]
public int CubeSize = 3;
// Start is called before the first frame update
void Start()
{
UpdateTiles();
}
// Using this you can already test the method without entering playmode
// via the context menu of the component
[ContextMenu(nameof(UpdateTiles)])
public void UpdateTiles()
{
// Destroy current children before spawning the new ones
foreach(var child in GetComponentsInChildren<Transform>().Where(child => child != transform)
{
if(!child) continue;
if(Application.isPlaying)
{
Destroy(child.gameObject);
}
else
{
DestroyImmediate(child.gameObject);
}
}
if (CubeSize < 1)
{
CubeSize = 1;
Debug.LogError("The cube can not be smaller than 1!");
}
else if (CubeSize > 30)
{
CubeSize = 30;
Debug.LogError("The cube should not be bigger than 30!");
}
// For making things easier to read I would use x,y,z here as well ;)
for (float x = 0; x < CubeSize; x++)
{
for (float y = 0; y < CubeSize; y++)
{
for (float z = 0; z < CubeSize; z++)
{
if (x == CubeSize - 1 || x == 0)
{
CreatePiece(x, y, z);
}
else if (y == CubeSize - 1 || y == 0)
{
CreatePiece(x, y, z);
}
else if (z == CubeSize - 1 || z == 0)
{
CreatePiece(x, y, z);
}
}
}
}
}
private void CreatePiece(float x, float y, float z)
{
var extends = 1 / (float)CubeSize;
var offset = (-0.5f + extends * 0.5f) * Vector3.one + extends * new Vector3(x,y,z);
var Piece = Instantiate(PiecePrefab, transform, false);
Piece.transform.localPosition = offset;
Piece.transform.localScale = extends * Vector3.one;
}