Question

我有很多数组。我可以将它们与for循环一起列出，但是，如果这些不同的数组中有相同的元素，则只需要显示每个元素一次。例如；

var array01 = [["Jack","92"],["Tom","74"],["Lily","100"],["Jonah","62"],["Lucy","83"]];
var array02 = [["Tom","94"],["Emma","70"],["Jack","100"],["Arnold","91"],["Kate","53"]];
var array03 = [["Jack","72"],["Tom","84"],["Emma","91"],["Jonah","92"],["Lucy","63"]];
var array04 = [["Emma","88"],["Marshall","82"],["Arnold","68"],["Ted","62"],["Lily","73"]];
var array05 = [["Jonah","87"],["Lucy","86"],["Kate","71"],["Jack","66"],["Lily","93"]];

我想像这样从最高值到最低值进行排序：

杰克：330
莉莉：266
汤姆：252
艾玛：249
约拿：241
露西：232
阿诺德：159
凯特：124
马歇尔：82
特德：62

Answer 1

您可以使用reduce通过将所有数组合并为一个来求和，然后应用sort()来基于score进行排序：

var array01 = [["Jack","92"],["Tom","74"],["Lily","100"],["Jonah","62"],["Lucy","83"]];
var array02 = [["Tom","94"],["Emma","70"],["Jack","100"],["Arnold","91"],["Kate","53"]];
var array03 = [["Jack","72"],["Tom","84"],["Emma","91"],["Jonah","92"],["Lucy","63"]];
var array04 = [["Emma","88"],["Marshall","82"],["Arnold","68"],["Ted","62"],["Lily","73"]];
var array05 = [["Jonah","87"],["Lucy","86"],["Kate","71"],["Jack","66"],["Lily","93"]];

var all=[...array01,...array02,...array03,...array04,...array05];

var result = Object.values(all.reduce((acc, [key, val])=>{
    acc[key] = acc[key] || {[key]:0};
    acc[key][key]+=+val;
    return acc;
},{})).sort((a,b)=>Object.values(b)[0]-Object.values(a)[0]);

console.log(result);

来自不同数组的相同元素的总和

1 个答案: