Question

我正在尝试敲打一个laravel api并以轻巧的方式显示它。

[
    {
        "doctor_name": "abhishek",
        "username": "abhishek",
        "uid": "aLSb7ebMfsfAxybrwq21kXjkcJM2",
        "fees": 500,
        "speciality": "Oncologist"
    },
    {
        "username": "amanboi",
        "uid": "wpTQALmZd5Yr5BVQyblNstjet1A3",
        "fees": 500,
        "speciality": "Oncologist",
        "doctor_name": "aman"
    }
]

当我尝试将其映射到模型时出现错误。这就是我的模型的样子

class Doctor {
  final String uid;
  final int fee;
  final String doctor_name;
  final String speciality;

  Doctor({this.uid, this.fee, this.doctor_name, this.speciality});

  factory Doctor.fromJson(Map<String, dynamic> json) {
    return Doctor(
      uid: json['userId'],
      fee: json['fee'],
      doctor_name: json['doctor_name'],
      speciality: json['speciality']
    );
  }
}

这是我的功能

Future<Doctor> doctorlist(String speciality ) async {
  final response = await http.post('http://192.168.0.101:8080/querysnapshot', body: {'speciality': speciality});
  print('got response successfully');
  if (response.statusCode == 200) {
    print(response.body);
    return Doctor.fromJson(json.decode(response.body));
  } else {
    throw Exception('Failed to load album');
  }
}

我得到的错误：

type 'List<dynamic>' is not a subtype of type 'Map<String, dynamic>'

Answer 1

您要将从API获得的List传递到模型中。返回列表。

Future<List> doctorlist(String speciality) async {
  final response = await http.post('http://192.168.0.101:8080/querysnapshot', body: {'speciality': speciality});
  print('got response successfully');
  if (response.statusCode == 200) {
    print(response.body);
    return json.decode(response.body);
  } else {
    throw Exception('Failed to load album');
  }
}

在ListView中，您可以执行以下操作

ListView.builder(
      itemBuilder: (BuildContext context, int index) {
        Doctor doctor = Doctor.fromJson(doctorList[index]);
        return Text(doctor.name);
      },
    );

'List <dynamic>'类型不是'Map <String，dynamic>类型的子类型

1 个答案: