Question

每当我运行命令时，它都会从字面上响应文本，而不是嵌入文本。这是我的代码：

@client.command()
async def item(ctx):
    items = [
    'embed = discord.Embed(title = "embed1", description = "test1")', 
    'embed = discord.Embed(title = "embed2", description = "test2")']
    randomitem = random.choice(items)
    await ctx.send (randomitem)

Answer 1

尝试一下：

@client.command()
async def item(ctx):
    items = [
    discord.Embed(title = "embed1", description = "test1"), 
    discord.Embed(title = "embed2", description = "test2")]
    randomitem = random.choice(items)
    await ctx.send(embed=randomitem) # embed= - for send discord.Embed

Answer 2

items列表中填充了字符串，而不是实际的嵌入对象。因此要获得所需的结果，您需要像这样删除嵌入对象周围的引号：

items = [ embed = discord.Embed(title = "embed1", description = "test1"), 
          embed = discord.Embed(title = "embed2", description = "test2")]

由于引号，Python只是将它们视为字符串。

编写代码的更好方法是

items = [discord.Embed(title = "embed1", description = "test1"),
         discord.Embed(title = "embed2", description = "test2")]
return ctx.send(embed=random.choice(items))

如何让Bot发送随机的预定义嵌入消息？

2 个答案: