我想像this那样绘制,其中x轴具有As,Cr,Cd,Pb列的值,并且箱形图使用鱼列进行颜色编码。可能吗?我的数据(csv):
fish,As,Cr,Cd,Pb
T. ilisha,0.023,0.002,0.039,0.004
G. chapra,0.224,0.011,0.048,0.005
M. vittatus,0.678,0.015,0.236,0.106
G. giuris,0.368,0.011,0.179,0.037
C. punctatus,0.274,0.016,0.124,0.035
M. armatus,0.461,0.015,0.476,0.039
P. ticto,0.437,0.021,0.533,0.048
S. cascasia,0.301,0.009,0.068,0.011
A. mola,0.454,0.016,0.179,0.065
H. fossilis,0.423,0.023,0.423,0.117
L.bata,0.295,0.019,0.287,0.039
W. attu,0.448,0.019,0.231,0.035
答案 0 :(得分:1)
这里是一种根据每个元素创建箱形图的方法,并带有指示每个鱼的位置。
pd.melt
用于创建数据框的“长格式”,便于seaborn处理。基本上会创建2个新列,其中一列具有元素名称,一列具有相应的值。每个原始行都会转换为4个新行。
from matplotlib import pyplot as plt
import pandas as pd
import seaborn as sns
from io import StringIO
df_data = StringIO('''fish,As,Cr,Cd,Pb
T. ilisha,0.023,0.002,0.039,0.004
G. chapra,0.224,0.011,0.048,0.005
M. vittatus,0.678,0.015,0.236,0.106
G. giuris,0.368,0.011,0.179,0.037
C. punctatus,0.274,0.016,0.124,0.035
M. armatus,0.461,0.015,0.476,0.039
P. ticto,0.437,0.021,0.533,0.048
S. cascasia,0.301,0.009,0.068,0.011
A. mola,0.454,0.016,0.179,0.065
H. fossilis,0.423,0.023,0.423,0.117
L.bata,0.295,0.019,0.287,0.039
W. attu,0.448,0.019,0.231,0.035''')
df = pd.read_csv(df_data)
df_long = pd.melt(df, 'fish', var_name='element', value_name='value')
sns.boxplot(x='element', y='value', palette=['lightgrey'], data=df_long, showfliers=False)
sns.scatterplot(x='element', y='value', hue='fish', palette='Set3', edgecolor='black', marker='D', data=df_long, zorder=3)
plt.show()
PS:为避免scatterplot
的标记重叠,可以使用stripplot
代替:
sns.stripplot(x='element', y='value', hue='fish', palette='Set3', linewidth=1, edgecolor='black', marker='D', data=df_long, zorder=3)
对于scatterplot
(而不是stripplot
),您可以为每条鱼使用不同的标记:
markers = ['o', 'v', '^', '8', '*', 'P', 'D', 'X', 's', 'p', '<', '>']
sns.scatterplot(x='element', y='value', hue='fish', palette='Set3', linewidth=1, edgecolor='black', markers=markers, data=df_long, zorder=3)