Question

是否有可能使程序在运行后返回其原始状态。例如，我在下面做了一个计算器脚本。是否可以使它在输出答案后重新开始，而不是用户必须退出脚本并再次运行它。代码：

class bcolors:
    Red = '\033[91m'
    Green = '\033[92m'
    Blue = '\033[94m'
    Cyan = '\033[96m'
    White = '\033[97m'
    Yellow = '\033[93m'
    Magenta = '\033[95m'
    Grey = '\033[90m'
    Black = '\033[90m'
    Default = '\033[99m'
#code for addition
def addition(x, y):
        return x + y
#code for subtraction
def subtraction(x, y):
        return x - y
#code for multiplication
def multiplication(x, y):
        return x * y
#code for division
def division(x, y):
        return x / y

print(bcolors.Blue + "Hey and welcome to my first python program")
print("This is a calculater I made in my spare time!")
print(bcolors.Magenta + "Simply type in your question here and you will get answer.")
print(bcolors.Red + "This program is made by and credited to Mohammad Al Nesef")
print(bcolors.Yellow + "1.addition")
print(bcolors.Yellow + "2.subtraction")
print(bcolors.Yellow + "3.multiplication")
print(bcolors.Yellow +"4.division")
choice = input(bcolors.Green + "Enter choice(1/2/3/4: ")
num1 = input(bcolors.Blue + "Enter first number: ")
num2 = (input(bcolors.Magenta + "Enter second number: "))
if choice == '1':
        print(float(num1), "+", float(num2), "=",  addition(num1,num2))

elif choice == "2":
        print(float(num1), "-", float(num2), "=", subtraction(num1,num2))

elif choice == "3":
        print(float(num1), "*", float(num2), "=", multiplication(num1,num2))

elif choice == "4":
        print(float(num1), "/", float(num2), "=", division(num1,num2))

else:
        print("Invalid Input")

Answer 1

您没有在此行中关闭括号： num2 = (input("Enter second number: ")

还请注意对文件使用相同的缩进。 PEP8符合性意味着有4个空格。

Answer 2

实际上，您不应该在第35行的“输入”之前给一个多余的括号

Column(
                children: <Widget>[
                  Padding(padding: EdgeInsets.fromLTRB(10, 0, 10, 20)),
                  Text('${e.phrase}', style: TextStyle(color: Colors.white60),),
                  Divider(height: 5, color: Colors.transparent,),
                  Text('${e.author}', style: TextStyle(color: Colors.white60),)
                ],
              ),

实际代码应为：

num2 =(input("Enter second number: ")

Answer 3

如果您正在寻找脚本本身的硬重启，而不希望通过更多的行来优雅地处理它，那么当您要重新开始时，请调用以下函数：

def restart_calc_script():
    import sys
    print("resetting the calculator.")
    import os
    os.execv(sys.executable, ['python'] + sys.argv)

是否有可能使python脚本循环并重新开始

3 个答案: