熊猫Apply Lambda导致TypeError:'int'对象不可下标

时间:2020-06-18 05:34:01

标签: python dataframe lambda

我有这个数据框的一个样本在这里:

Blockquote

此代码有问题。我收到以下错误消息:

Traceback (most recent call last):   File "C:/Users/....py", line 12, in <module>
 dfF['CCRYear'] = dfF['Year'].apply(lambda x: 'True' if x['Year'] == x['MaxSS Year'] else 'False')   File "C:\Users\....py", line 3848, in apply
 mapped = lib.map_infer(values, f, convert=convert_dtype)   File "pandas\_libs\lib.pyx", line 2329, in pandas._libs.lib.map_infer   
 File "C:/Users/....py", line 12, in <lambda>
 dfF['CCRYear'] = dfF['Year'].apply(lambda x: 'True' if x['Year'] == x['MaxSS Year'] else 'False')
 TypeError: 'int' object is not subscriptable

“年”和“最大SS年”列均为int64数据类型。这是下面的代码:

import pandas as pd
import numpy as np

def cached_date_parser(s):
    if s in cache:
        return cache[s]
    dt = pd.to_datetime(s, format='%Y%m%d', coerce=True)
    cache[s] = dt
    return dt

dfF = pd.read_csv(r'C:\\Users\\....C_14.csv', parse_dates = [1], header='infer')
dfF['CCRYear'] = dfF['Year'].apply(lambda x: 'True' if x['Year'] == x['MaxSS Year'] else 'False')

1 个答案:

答案 0 :(得分:1)

代码的问题是您在单列上使用https://tonycosmosdb.mongo.cosmos.azure.com:443/,并且正在为其编制索引。

看看您在做什么,只需在您的apply()中打印x

lambda

它将在下面输出

df['Year'].apply(lambda x: print(x))

您的代码正在尝试索引整数值2017 2018 2018 2015 2015 2015 。在此x['Year']中,是整数年,例如2018、2019等。

将此更改为

x

这个

dfF['CCRYear'] = dfF['Year'].apply(lambda x: 'True' if x['Year'] == x['MaxSS Year'] else 'False')

使用np.where()

dfF['CCRYear'] = dfF['Year'] == dfF['MaxSS Year']