Question

我该如何编写一个带有两个参数（数组responses和string）的函数，并且对于isEssayQuestion是正确的，比较string参数作为response键值的参数，如果它们与任何人匹配，则返回true，如果与任何人都不匹配，则返回false。

const responses = [
  {
    question: 'What is the phase where chromosomes line up in mitosis?',
    response: 'Metaphase',
    isCorrect: true,
    isEssayQuestion: false
  },
  {
    question: 'What anatomical structure connects the stomach to the mouth?',
    response: 'Esophagus',
    isCorrect: true,
    isEssayQuestion: false
  },
  {
    question: 'What are lysosomes?',
    response: 'A lysosome is a membrane-bound organelle found in many animal cells. They are spherical vesicles that contain hydrolytic enzymes that can break down many kinds of biomolecules.',
    isCorrect: true,
    isEssayQuestion: true
  },
  {
    question: 'True or False: Prostaglandins can only constrict blood vessels.',
    response: 'True',
    isCorrect: false,
    isEssayQuestion: false
  }
];

// example
checkForPlagiarism(responses, 'spherical vesicles that contain hydrolytic enzymes'); //> true
checkForPlagiarism(responses, 'this string does not appear in the responses'); //> false

// my code
function checkForPlagiarism(test, answerKey) {
  for (let i = 0; i < test.length; i++) {
    let question = test[i];
    if (question.isEssayQuestion) {
      let response = question.response;
      return response.includes(answerKey);
    }
  }
}

Answer 1

您不需要遍历对象，因为给定的响应本身就是数组。

除了return语句之外，您所做的一切对我来说似乎还不错。因此，请将您的return语句添加到字符串匹配逻辑的if中。

function checkForPlagiarism(test, answerKey) {
  for (let i = 0; i < test.length; i++) {
    let question = test[i];
    if (question.isEssayQuestion) {
      let response = question.response;
      if (response.includes(answerKey)) return true;
    }
  }
  return false
}

Answer 2

您的代码已经返回了正确的值（如果找到匹配项，则返回true；如果未找到匹配项，则返回false），如果未找到匹配项，则只需在for循环后添加return false即可（没有isEssayQuestion：true）。对您的函数调用返回的值进行console.log（）检出。

示例：

console.log（checkForPlagiarism（响应，“包含水解酶的球形囊泡”）） console.log（checkForPlagiarism（响应，“此字符串未出现在响应中”））

如何遍历对象中的特定键？

2 个答案: