如何使用php获取此查询的第一个结果?我希望列表按降序返回时返回的第一个结果。
$sql2 = "SELECT orderID FROM orders WHERE 'customerID' = '".$_SESSION['accountID']."' ORDER BY
'orderID' DESC";
$lastorder = mysqli_query($sql2);
谢谢!
答案 0 :(得分:3)
只需将LIMIT 1
添加到SQL
答案 1 :(得分:0)
使用LIMIT
:
'SELECT orderID FROM orders WHERE customerID = "' . $_SESSION['accountID'] . '" ORDER BY orderID DESC LIMIT 1'
答案 2 :(得分:0)
查询:
$query = "SELECT MAX(orderID) as orderID
FROM orders
WHERE customerID = '" . $_SESSION['accountID'] . "'";
如果customerID是一个数字,则可以删除单引号以进行查询:
$query = "SELECT MAX(orderID) as orderID
FROM orders
WHERE customerID = " . $_SESSION['accountID'];
则...
// include database_link since you are not using OO-style call.
$result = mysqli_query($database_link, $query);
$row = $result->fetch_object();
$orderID = $row->orderID;