我做以下
my_hash = Hash.new
my_hash[:children] = Array.new
然后我有一个函数,每次写给孩子时都会调用自己一些时间
my_hash[:children] = my_replicating_function(some_values)
如何在不覆盖已写入的数据的情况下编写?
这就是整个函数的样子
def self.build_structure(candidates, reports_id)
structure = Array.new
candidates.each do |candidate, index|
if candidate.reports_to == reports_id
structure = candidate
structure[:children] = Array.new
structure[:children] = build_structure(candidates, candidate.candidate_id)
end
end
structure
end
答案 0 :(得分:3)
也许这个:
structure[:children] << build_structure(candidates, candidate.candidate_id)
答案 1 :(得分:2)
structure[:children] << build_structure(candidates, candidate.candidate_id)