Question

在获取基于访问码的访问令牌期间，我面临来自PayPal的400错误请求响应。我通过下面的参考链接https://developer.paypal.com/docs/connect-with-paypal/integrate/#1-create-the-app

我完美地遵循了5个步骤，但是第一个步骤遇到了问题。 6.参见下面的代码：

请求零件：

$curl = curl_init();

$base_token = "{client_id:secret}";

$data = array(
    CURLOPT_URL => "https://api.sandbox.paypal.com/v1/oauth2/token",
    CURLOPT_RETURNTRANSFER => true,
    CURLOPT_CUSTOMREQUEST => "POST",
    CURLOPT_POSTFIELDS => array(
        'grant_type' => 'authorization_code',
        'code' => '{authorization_code}'
    ),
    CURLOPT_HTTPHEADER => array(
        "Authorization: Basic ".$base_token,
    ),
);
curl_setopt_array($curl,$data );
$response = curl_exec($curl);
curl_close($curl);

响应部分：

stdClass Object (
    [name] => Bad Request
    [debug_id] => 5837077aa8787
    [message] => java.lang.IllegalArgumentException
    [details] => Array
        (
        )
)

Answer 1

将数组传递给CURLOPT_POSTFIELDS会将内容类型设置为multipart/form-data。这是错误的。

您需要将查询字符串传递给CURLOPT_POSTFIELDS。

CURLOPT_POSTFIELDS => http_build_query(array(
        'grant_type' => 'authorization_code',
        'code' => '{authorization_code}'
    )),

Answer 2

解决问题，请参见下面的代码：

$base_token = '{client_id:secret}';

$curl = curl_init();

$data = array(
    CURLOPT_URL => "https://api.sandbox.paypal.com/v1/oauth2/token",
    CURLOPT_RETURNTRANSFER => true,
    CURLOPT_CUSTOMREQUEST => "POST",
    CURLOPT_SSL_VERIFYPEER => false,
    CURLOPT_POSTFIELDS => http_build_query(array(
        'grant_type'=>'authorization_code',
        'code'=> $request->code,
    )),
    CURLOPT_HTTPHEADER => array(
        "Content-Type: application/x-www-form-urlencoded",
    ),
    CURLOPT_USERPWD => $base_token
);

curl_setopt_array($curl, $data);

$response = curl_exec($curl);
curl_close($curl);

与PayPal连接：获取状态400（错误请求）

2 个答案: