使用不是Sequelize.Model错误的子类的东西进行调用

时间：2020-06-07 17:23:41

标签： javascript node.js sequelize.js associations

你好我的地址模型 

const { DataTypes } = require('sequelize');  
const sequelize = require('../../../db/connection');  
var BorrowerInfo = require('../../models/borrowerInfo/BorrowerInfo')
const Address = sequelize.define('addresses', {
    id: {
        type: DataTypes.INTEGER,
        primaryKey: true,
        autoIncrement: true,
        allowNull: false,
    },
    street: {
        type: DataTypes.STRING,
        allowNull: false
    },
    unit: {
        type: DataTypes.STRING,
        allowNull: false
    },
    city: {
        type: DataTypes.STRING,
        allowNull: false
    },
    state: {
        type: DataTypes.STRING,
        allowNull: false
    },
    zip: {
        type: DataTypes.STRING,
        allowNull: false
    },
    country: {
        type: DataTypes.STRING,
        allowNull: false
    },
},
    {
        freezeTableName: true
    },
    {
    }
);
Address.associate = (models) => {
    Address.belongsToMany(BorrowerInfo, {
        through: 'BorrowerAddresses',
        as: 'address',
        foreignKey: 'addressId'
      });
  };
module.exports = Address;

我的借款人模式 

 const { DataTypes } = require('sequelize');
const sequelize = require('../../../db/connection');

const Address = require('../../models/common/Address')


const BorrowerInfo = sequelize.define('borrower_info', {
    id : {
        type: DataTypes.INTEGER,
        primaryKey: true,
        autoIncrement: true ,
        allowNull: false,
    },
    loanAppNo : {
        type: DataTypes.STRING,
        allowNull: false
    },
    firstName: {
        type: DataTypes.STRING,
        allowNull: false
    },
    lastName: {
        type: DataTypes.STRING,
        allowNull: false
    },
    middleName:{
        type: DataTypes.STRING,
        allowNull: false
    },
    suffix: {
        type: DataTypes.STRING,
        allowNull: false
    },
    ssn: {
        type: DataTypes.STRING,
        allowNull: false
    },
    dob: {
        type: DataTypes.DATE,
        allowNull: false
    },
    citizenship: {
        type: DataTypes.STRING,
        allowNull: false
    },
    maritalStatus: {
        type: DataTypes.ENUM('1','2','3'),
    },
    noOfDependantChilds: {
        type: DataTypes.INTEGER,
        allowNull: false
    },
    agesDependantChilds: {
        type: DataTypes.STRING,
        allowNull: false
    },
    contactInfo: {
        type: DataTypes.JSON,
        allowNull: false
    }, 
    createdAt: {
        type: DataTypes.NOW,
    }
},
    { 
        timestamps: false,
        freezeTableName: true
    },
    {
    }
);

    BorrowerInfo.belongsToMany(Address, {
        through: 'borrower_addresses',
      });
module.exports = BorrowerInfo;

我的借款人地址模型 

const {
    DataTypes
} = require('sequelize');
var Addresses = require('../common/Address')
const sequelize = require('../../../db/connection');

const BorrowerAddresses = sequelize.define('borrower_addresses', {

id: {
    type: DataTypes.INTEGER,
    primaryKey: true,
    autoIncrement: true,
    allowNull: false,
},
borrowerInfoId: {
    type: DataTypes.INTEGER,
    allowNull: false
},
type: {
    type: DataTypes.ENUM('current', 'former', 'mailing'),
    allowNull: false
},
addressId: {
    type: DataTypes.INTEGER,
    allowNull: false
},
howLongAtCurrentAddress: {
    type: DataTypes.INTEGER,
    allowNull: false
},
housing: {
    type: DataTypes.ENUM('1', '2', '3'),
},
rentPerMonth: {
    type: DataTypes.FLOAT,
    allowNull: false
},
createdAt: {
    type: DataTypes.NOW,
}
}, {
    timestamps: false,
    freezeTableName: true
});

module.exports = BorrowerAddresses;

错误：使用不是Sequelize.Model的子类的东西调用了rower_info.belongsToMany

当我在下面的借款人信息模型中安慰地址模型时
BorrowerInfo：类扩展了模型{} 地址：{}

地址模型没有扩展模型类

但是当我在地址模型中合并借款人信息模型时，它正在扩展模型类，这是什么问题，请指导我如何摆脱此错误

请标记一些可以提供帮助的人

2 个答案:

答案 0 :(得分：0)

您的模型定义是实际的模型名称。因此，使模型名称与下面的定义相同。

module.exports = (sequelize, DataTypes) => {
  const BorrowerInfo = sequelize.define('BorrowerInfo', {
     id : {
    type: DataTypes.INTEGER,
    primaryKey: true,
    autoIncrement: true ,
    allowNull: false,
    },
    ....
   {
    tableName: 'borrower_info', // you can pass your tablename here
  });
  return BorrowerInfo;
};

如果模型名称为Address，则sequelize会将模型映射到名为Addresses的表，您可以通过显式传递表名来防止该行为。

答案 1 :(得分：0)

如果有人卡在这里，我找到了解决方法

实际上，我必须在单个文件中初始化所有模型，而不是例如从单个文件中导入它。

文件：index.js 

'use strict';
const fs = require('fs');
const path = require('path');
const basename = path.basename(module.filename);
const sequelize = require('../../db/connection');

let db = {};
// borrower info
fs.readdirSync(`${__dirname}/borrowerInfo`)
    .filter(function (file) {
        return (file.indexOf('.') !== 0) && (file !== basename);
    })
    .forEach(function (file) {
        if (file.slice(-3) !== '.js') return;
        let model = sequelize['import'](path.join(`${__dirname}/borrowerInfo`, file));
        db[model.name] = model;
    });


//loan team
fs.readdirSync(`${__dirname}/loanTeam`)
    .filter(function (file) {
        return (file.indexOf('.') !== 0) && (file !== basename);
    })
    .forEach(function (file) {
        if (file.slice(-3) !== '.js') return;
        let model = sequelize['import'](path.join(`${__dirname}/loanTeam`, file));
        db[model.name] = model;
    });

// common
fs.readdirSync(`${__dirname}/common`)
    .filter(function (file) {
        return (file.indexOf('.') !== 0) && (file !== basename);
    })
    .forEach(function (file) {
        if (file.slice(-3) !== '.js') return;
        let model = sequelize['import'](path.join(`${__dirname}/common`, file));
        db[model.name] = model;
    });


// role
fs.readdirSync(`${__dirname}/role`)
    .filter(function (file) {
        return (file.indexOf('.') !== 0) && (file !== basename);
    })
    .forEach(function (file) {
        if (file.slice(-3) !== '.js') return;
        let model = sequelize['import'](path.join(`${__dirname}/role`, file));
        db[model.name] = model;
    });

// user
fs.readdirSync(`${__dirname}/user`)
    .filter(function (file) {
        return (file.indexOf('.') !== 0) && (file !== basename);
    })
    .forEach(function (file) {
        if (file.slice(-3) !== '.js') return;
        let model = sequelize['import'](path.join(`${__dirname}/user`, file));
        db[model.name] = model;
    });

Object.keys(db).forEach(function (modelName) {
    if (db[modelName].associate) {
        db[modelName].associate(db);
    }
});


db.sequelize = sequelize;
module.exports = db;

导入其他文件 

const models = require('../models/index')
const exampleTable = models.tableName
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