Question

答案为here。

我在笛卡尔平面上有以下几点

points = [(4, 5), (-0, 2), (4, 7), (1, -3), (3, -2), (4, 5), (3, 2), (5, 7), (-5, 7), (2, 2), (-4, 5), (0, -2), (-4, 7), (-1, 3), (-3, 2), (-4, -5), (-3, 2), (5, 7), (5, 7), (2, 2), (9, 9), (-8, -9)]

我需要使用欧几里得距离找到最接近中心的点。

到目前为止，我已经做到了：

import math
euclidean_distance=[]
distance = math.sqrt(sum([((x+y)**2) for (x,y) in points]))

for (x,y) in points:
    int(distance)
    euclidean_distance.append(distance)

min_distance=min(euclidean_distance)

print(distance)
print(euclidean_distance)
print(min_distance)

结果为：

38.71692136521188
[38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188]
38.71692136521188

为什么不计算列表中每个点的欧几里得距离？

Answer 1

最后，我这样做并为我工作：

.aligncenter {
	text-align: center !important;
}

如何使用欧几里得距离计算两点之间的距离？

1 个答案: