Question

在使用jQuery之前，我可以做一个链接动画，延迟时间如下：

$("#element").delay(45).animate({ }, 45)
             .delay(45).animate({ }, 45)
             .delay(45).animate({ }, 45);

现在，自从更新到v1.6.1以来，它没有像以前那样做，它现在跳到最后一个动画。忽略之前的陈述。我知道我可以为每个动画做一个不完整的回调，但这只是弄乱了：

$("#element").delay(45).animate({ }, 45, function(){
    $("#element").delay(45).animate({ }, 45, function(){
        $("#element").delay(45).animate({ }, 45);
    })
})

有谁知道如何以简单干净的方式实现这一目标？

Answer 1

修改：为您添加了Fiddle

我刚才写了这段代码，也许它对你有用吗？（对于凌乱的缩进感到抱歉）

/**
 * Queue.js
 *
 * @author Arend van Waart
 *
 *  This will allow for events to be queued by timestamp
 *
 * @example
 *  queue({
 *  1000: function () {
 *       // element a na 10ms uitfaden, en daar 100ms over doen
 *       $('#menu').fadeOut(2000);
 *  },
 *  500: function () {
 *    // na 50 ms element b en c inzoemen
 *    $('#content').slideUp(2000);
 * }
 * });
 */

var queue = function(queue){
    var self = this;
    // queue
    this.queue = queue;
    // time passed is 0
    this.timePassed = 0;
    // time in ms to sleep between checks.
    this.sleep = 100;

    var time = new Date();
    this.lastTime = time.getTime();
    this.iterate = function(){
        var total = 0;
        var time = new Date();

        // how much time has passed since we slept?
        self.timePassed = self.timePassed + (time.getTime() - self.lastTime);
        self.lastTime = time.getTime();
        for (var t in self.queue){
            if (t <= self.timePassed){
                self.queue[t]();
                delete(self.queue[t]);
            }
            total++;
        }

        if (total == 0){
            return;
        }else{
            setTimeout(self.iterate, self.sleep);
        }
    }
    this.iterate();
}

Answer 2

这是第二种方式。我把它贴在另一个答案中，因为它更复杂，也许不那么漂亮。要使用它，请参阅：http://jsfiddle.net/LMptt/1/

用法：使用带+或 - 的字符串表示相对时间戳。该顺序对相对时间戳（相对于之前的操作）很重要。使用“+0”或“-0”表示与前一个时间戳相同的时间戳。绝对时间戳（整数）可以放在列表中的任何位置。

$(document).ready(function ()
{
    queue([
        [2000, function () {  $('.two').slideUp(); }],
        ['-1000', function () {  $('.one').slideUp(); }],
        [3000, function () {  $('.three').slideUp(); }],
        ['+1000', function () {  $('.four').slideUp(); }]
    ]);

});

/**
 * Queue.js
 *
 * @author Arend van Waart
 *
 *  This will allow for events to be queued by (relative) timestamp
 */

 function queue (queue){
    var self = this;
    // queue
    this.queue = queue;
    // time passed is 0
    this.timePassed = 0;
    // time in ms to sleep between checks.
    this.sleep = 100;

    var time = new Date();
    this.lastTime = time.getTime();
    this.iterate = function(){
        var total = 0;
        var time = new Date();

        // how much time has passed since we slept?
        self.timePassed = self.timePassed + (time.getTime() - self.lastTime);
        self.lastTime = time.getTime();

        for (var i in self.queue) {
            if (self.queue[i][0] <= self.timePassed){
                self.queue[i][1]();
                self.queue.splice(i,1);
            } else {
                // added sorting now, so we don't have to evaluate the rest.
                break;
            }
        }

        if (self.queue.length == 0){
            return;
        }else{
            setTimeout(self.iterate, self.sleep);
        }
    }


    this.parseRelative = function ()
    {
        var absoluteQueue = [];
        var lastAbsolute = 0;
        for (var i in queue)
        {
           var absolute;
           var firstChar = String(queue[i][0]).charAt(0);
           if (firstChar == "+" ||  firstChar == "-")
           {
              absolute = lastAbsolute + parseInt(queue[i][0]);
           } else {
              absolute = parseInt(queue[i][0]);
           }
           lastAbsolute = absolute;
           absoluteQueue.push([absolute, queue[i][1]]);
        }
        this.queue = absoluteQueue;
    }
    this.sort = function (a,b)
    {
        return a[0] - b[0];
    }

    this.parseRelative();
    this.queue.sort(this.sort);
    this.iterate();
}

jQuery链接动画没有插件

2 个答案: