合并同一列中的各种数据框

时间:2020-05-26 17:03:38

标签: r dataframe merge dplyr

我正在通过一个公用键列(第一列)将两个数据帧合并在一起,但是我想基于上一列中的第二列再次添加相同的列:

clusering_matrix_example <- data.frame(BGC = c("BGC1", "BGC2", "BGC3", "BGC4"), Family = c("10","20","30","40"))
network_matrix_example <- data.frame(BGC1 = c("BGC1", "BGC1", "BGC1", "BGC2", "BGC2", "BGC2", "BGC3", "BGC3", "BGC3", "BGC4", "BGC4", "BGC4"),
                                     BGC2 = c("BGC2", "BGC3", "BGC4", "BGC1", "BGC3", "BGC4", "BGC1", "BGC2", "BGC4", "BGC1", "BGC2", "BGC3"),
                                     score = c(1,2,3,1,4,5,2,4,6,3,5,6))
network_output_example <- merge(network_matrix_example, clusering_matrix_example, by.x= "BGC1", by.y = "BGC")

network_output_example <- merge(network_matrix_example, clusering_matrix_example, by.x= "BGC2", by.y = "BGC")

第一个DF的输出示例

BGC1  | BGC2 | score |Family
BGC1    BGC2    1     10
BGC1    BGC3    2     10
BGC1    BGC4    3     10
BGC2    BGC1    1     20
BGC2    BGC3    4     20
BGC2    BGC4    5     20
BGC3    BGC1    2     30
BGC3    BGC2    4     30
BGC3    BGC4    6     30
BGC4    BGC1    3     40
BGC4    BGC2    5     40
BGC4    BGC3    6     40

所需的输出DF

BGC1  | BGC2 | score |Family1 | Family2
BGC1    BGC2    1     10        20
BGC1    BGC3    2     10        30
BGC1    BGC4    3     10        40
BGC2    BGC1    1     20        10
BGC2    BGC3    4     20        30
BGC2    BGC4    5     20        40
BGC3    BGC1    2     30        10
BGC3    BGC2    4     30        20
BGC3    BGC4    6     30        40
BGC4    BGC1    3     40        10
BGC4    BGC2    5     40        20
BGC4    BGC3    6     40        40

这些长度可能也不同,所以我要合并all = TRUE吗?

2 个答案:

答案 0 :(得分:1)

只需在第二次合并中更改名称

clusering_matrix_example <- data.frame(BGC = c("BGC1", "BGC2", "BGC3", "BGC4"), Family = c("10","20","30","40"))

ne1 <- data.frame(BGC1 = c("BGC1", "BGC1", "BGC1", "BGC2", "BGC2", "BGC2", "BGC3", "BGC3", "BGC3", "BGC4", "BGC4", "BGC4"),
                                     BGC2 = c("BGC2", "BGC3", "BGC4", "BGC1", "BGC3", "BGC4", "BGC1", "BGC2", "BGC4", "BGC1", "BGC2", "BGC3"),
                                     score = c(1,2,3,1,4,5,2,4,6,3,5,6))

ne2 <- merge(ne1, clusering_matrix_example, by.x= "BGC1", by.y = "BGC")

network_output_example <- merge(ne2, clusering_matrix_example, by.x= "BGC2", by.y = "BGC")

答案 1 :(得分:0)

setState

看起来像您想要的输出。