Question

我正在了解弹簧靴，但是我因这个问题而停下来。我有一个@JsonSubTypes的人员抽象类，一个Client和Seller类，它扩展了@JsonTypeName的Person。所有请求均返回错误：尝试解析子类型时缺少类型ID。

人员班

<!-- language: python -->

def format_name(first_name, last_name):
if last_name != '' and first_name != '':
    string = "Name: " + last_name + ", " + first_name
elif first_name != ' ' or last_name !=' ':
    string = ("Name: " + first_name + last_name)
else:
    string = ''

return string

客户端类

@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = As.PROPERTY, property = "type")
@JsonSubTypes({
    @JsonSubTypes.Type(value = Client.class, name = "client"),
    @JsonSubTypes.Type(value = Seller.class, name = "seller")
//    @JsonSubTypes.Type(value = Provider.class, name = "provider"),
})
public abstract class Person implements Comparable<Person>{
    @Id
    @Field("_id")
    @JsonIgnore
    private String code;
    private String name;
    private String phone;
    private String email;
    @Field("created_at")
    private DateTime registerDate;

    public Person(String name, String phone, String email) {
        this.name = name;
        this.phone = phone;
        this.email = email;
    }

卖方课程

@Document("clients")
@JsonTypeName("client")
public class Client extends Person{
    @Indexed(unique=true)
    private String cpf;
    @Field("credit_limit")
    private Double creditLimit;

    public Client(String name, String phone, String email, String cpf,
            Double creditLimit) {
        super(name, phone, email);
        this.cpf = cpf;
        this.creditLimit = creditLimit;
    }

初始方法

@Document("sellers")
@JsonTypeName("seller")
public class Seller extends Person {
    @Indexed(unique=true)
    private String cpf;
    @Field("monthly_goal")
    private Double monthlyGoal;

    public Seller(String name, String phone, String email, String cpf,
            Double monthlyGoal) {
        super(name, phone, email);
        this.cpf = cpf;
        this.monthlyGoal = monthlyGoal;
    }

Answer 1

似乎您缺少在JSON请求正文中提交"type":"client"字段。但是，您还需要在Person，Client，Seller类中提供默认构造函数，或使用@JsonCreator批注标记可用的构造函数：

// Client with explicit creator
    @JsonCreator
    public Client(
            @JsonProperty("name") String name, 
            @JsonProperty("phone") String phone, 
            @JsonProperty("email") String email, 
            @JsonProperty("cpf") String cpf,
            @JsonProperty("creditLimit") Double creditLimit) {
        super(name, phone, email);
        this.cpf = cpf;
        this.creditLimit = creditLimit;
    }
// ------
// seller: use default constructor (also to be added in `Person`) for Jackson
public Seller() {}

// person
public Person() {}

@JsonTypeName无法正常工作，并在尝试解析子类型时返回缺少的类型ID

1 个答案: