ldap嵌套组成员资格

时间:2011-06-01 03:03:29

标签: active-directory ldap nested

是否可以创建一个LDAP查询,该查询将返回(或检查)嵌套组中的用户?例如UserA是GroupA的成员,GroupA是GroupB的成员。我希望GroupB上的查询返回UserA是一个成员。仅限LDAP。服务器是Active Directory。

3 个答案:

答案 0 :(得分:71)

是,使用LDAP_MATCHING_RULE_IN_CHAIN匹配规则(OID 1.2.840.113556.1.4.1941)。例如:

(memberOf:1.2.840.113556.1.4.1941:=cn=group,cn=users,DC=x)

请参阅http://msdn.microsoft.com/en-us/library/aa746475%28VS.85%29.aspx

答案 1 :(得分:7)

在我的案例中使用memberOf:1.2.840.113556.1.4.1941:=时,您必须使用论坛的完整专有名称CN=MyGroup,OU=User,OU=Groups,OU=Security,DC=domain,DC=com才是整个专有名称

(&(objectCategory=person)(objectClass=user)(memberOf:1.2.840.113556.1.4.1941:=CN=MyGroup,OU=User,OU=Groups,OU=Security,DC=domain,DC=com))

您可以通过运行以下代码并输入此过滤器来获取您的组的可分辨名称     的(及(objectClass的=基团)(名称= MyGroup的))

Imports System.DirectoryServices

Module Module1

Sub Main()
    Dim run As Boolean = True
    Dim Filter As String
    While run
        Console.WriteLine("Enter Filter:")
        Filter = Console.ReadLine()
        If Filter = "exit" Then
            run = False
        Else
            checkFilter(Filter)
        End If
    End While
End Sub

Function checkFilter(Filter As String) As Boolean
    Dim search As New DirectorySearcher("LDAP://dc=Domain,dc=com")
    Try
        search.Filter = Filter
        search.PropertiesToLoad.Add("name")
        search.PropertiesToLoad.Add("distinguishedName")
        search.SearchScope = SearchScope.Subtree
        Dim results As SearchResultCollection = search.FindAll()
        If results Is Nothing Then
            Console.WriteLine("Nothing")
            Return False
        Else
            If results.Count() = 0 Then
                Console.WriteLine("non found")
            End If
            Dim result As SearchResult
            For Each result In results
                Console.WriteLine(result.Properties("name")(0).ToString())
                Console.WriteLine(result.Properties("distinguishedName")(0).ToString())
                'For Each prop In result.Properties("members")
                '    Console.WriteLine(prop.ToString())
                'Next
            Next
            Console.WriteLine(String.Format("{0} Users Found", results.Count()))
        End If
    Catch ex As Exception
        Console.WriteLine(ex.Message)
    End Try
    Return True
End Function

End Module

答案 2 :(得分:1)

作为您的问题,查询应为

(&(memberOf:1.2.840.113556.1.4.1941:={0})(objectCategory=person)(objectClass=user)(sAMAccountName={1}))

{0}是嵌套组,应该是专有名称

{1}是您想要的用户 sAMAccountName (您可以在(sAMAccountName={1})中使用除sAMAccountName之外的任何其他用户属性)

如果用户是嵌套组

的成员,那么您将获得响应的用户详细信息