随机不打印正确的最大值和最小值

时间:2020-05-17 01:22:48

标签: java for-loop random max min

我正试图允许用户将他们想要的最大和最小输入到一个随机数的新文件中。但是,当我运行程序时,生成的随机数始终小于所需的最小值。例如,如果max = 10且min = 5,我只能得到0到5之间的数字。我想知道如何才能得到5到10之间的数字。我的假设是找到max和min该函数应为(max-min)+1,但对我而言不起作用。

import java.io.*;
import java.util.*;

public class chooseRandNum{
    public static void main(String[] args){
        Random rand = new Random();
        Scanner key = new Scanner(System.in);
        System.out.println("How many random numbers do you want? ");
        int totalRand = key.nextInt();
        System.out.println("What is the smallest random number? ");
        int smallRand = key.nextInt();
        System.out.println("What is the largest random number? ");
        int largeRand = key.nextInt();
        System.out.println("What filename do you want to use? ");
        String fname = key.nextLine();

        File outputFile = new File(fname);
        PrintStream outputStream = null;

        try{
            outputStream = new PrintStream(outputFile);
        }

        catch (Exception e){
            System.out.println("File not found " + e);
            System.exit(1);
        }


        for(int i = 0; i <= 5; i++){
            for(int j = 0; j <= totalRand; j++){
                int n = rand.nextInt((largeRand - smallRand) + 1);
                outputStream.print(n + ",");
            }
            outputStream.println();
        }   
    }
}

2 个答案:

答案 0 :(得分:1)

替换

rand.nextInt((largeRand - smallRand) + 1)

使用

rand.nextInt(largeRand - smallRand + 1) + smallRand

答案 1 :(得分:0)

问题是您没有正确生成随机数。 rand.nextInt(max-min+1)+min应该以[min,max]给出一个随机整数,因为rand.nextInt(int)调用提供了一个整数[0,int)Java Documentarion of java.util.Random.nextInt