我的msbuild脚本中有以下代码:
<?xml version="1.0" encoding="utf-8"?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" ToolsVersion="4.0" InitialTargets="Build">
<PropertyGroup>
<Configuration Condition=" '$(Configuration)' == '' ">Debug</Configuration>
<SolutionName>CommTrac.Web\CommTrac.Web</SolutionName>
<SolutionFileName>$(SolutionName).csproj</SolutionFileName>
</PropertyGroup>
<Target Name="Build">
<Message Text="Building the solution"/>
<MSBuild Projects="$(SolutionFileName)" ContinueOnError="false" Properties="Configuration=$(Configuration)" />
</Target>
<Target Name="CopyOutput" DependsOnTargets="Build">
<ItemGroup>
<BinFolder Exclude="*.pdb" Include="$(ProjectDir)bin\**\*.*"/>
<BuildOutputFolder Include="C:\BuildOutput" />
</ItemGroup>
<Message Text="Copying from directory: $(BinFolder)"/>
<Copy SourceFiles="$(BinFolder)" DestinationFolder="$(BuildOutputFolder)"/>
</Target>
</Project>
由于某种原因,它不会将文件复制到我的输出目录。我尝试了所有类似的 我看到过与此问题类似的其他问题的解决方案。有人有什么想法吗?
答案 0 :(得分:4)
BindFolder和BuildOutputFolder是项目,而不是属性。所以你需要使用@(BindFolder)和@(BuildOutputFolder)而不是'$'来引用它们。