Question

我有两个表，新表和已注册表，我想要的是在对布尔值进行更新（已接受= 1，将其发送到已注册）时以及在信息重新插入后将注册的新内容。要再次注册删除相同的对象，请尝试创建一个可以执行此操作的触发器，但是尽管这样做可以使我很好地保存，但触发器不会前进并且不会执行操作

BEGIN
CREATE TRIGGER `trigger_1` AFTER UPDATE ON `new` 
FOR EACH ROW INSERT INTO registered (Num_Registered, Name_Registered, Type_Id, Semes_Registered, Fac_Registered, Pass) SELECT Mat_New, Name_New, Id_New, Semes_New, Fac_New, Pass_New FROM new WHERE Accepted=1;

DELETE FROM new WHERE Accepted=1 OR Accepted=0;//Here taking into account that 0 is rejected and deleted, and 1 is accepted and sent to registered
END;

以相同的方式，我尝试制作2个触发器（一个触发器将一个表插入到另一个表，然后另一个触发器在插入后首先删除了表中的表），但它们仅彼此冲突*错误1442-无法更新存储函数/触发器中的新表，因为调用该存储函数/触发器的语句已在使用该表

CREATE TRIGGER `trigger_1` BEFORE UPDATE ON `new`
FOR EACH ROW INSERT INTO registered (Num_Registered, Name_Registered, Type_Id, Semes_Registered, Fac_Registered, Pass) SELECT Mat_New, Name_New, Id_New, Semes_New, Fac_New, Pass_New FROM new WHERE Accepted=1;


CREATE TRIGGER `trigger_2` AFTER UPDATE ON `new`
 FOR EACH ROW DELETE FROM new WHERE Accepted=1 OR Accepted=0;//Here taking into account that 0 is rejected and deleted, and 1 is accepted and sent to registered

Answer 1

显然，插入到registrations表中很简单。而且我能理解您为什么要这样做的原因。例如，您可能具有“被接受”人员的其他数据。您可能只希望外键关系“被接受”。

挑战在于您希望update变成delete。我认为在MySQL触发器中这是不可能的。但是一个简单的替代方法是只使用视图：

create view v_new as
    select n.*
    from new n
    where n.accepted <> 1;

这还具有以下优点：即使使用视图的用户看不到新用户，您也可以对其进行记录。

插入后触发删除

1 个答案: