Question

我收到这个ajax响应：

{"0":{"id":1,"value":"73.0","tracker_id":1,"created_at":"2020-05-04 20:13:22","updated_at":"2020-05-04 20:13:22"},"7":{"id":8,"value":"73.0","tracker_id":1,"created_at":"2020-05-03 20:13:22","updated_at":"2020-05-04 20:13:22"},"8":{"id":9,"value":"73.0","tracker_id":1,"created_at":"2020-05-06 19:48:31","updated_at":"2020-05-06 19:48:31"}}

我只想从每一行中提取值。这显然没有用：

for (i = 0; i < data.length; i++) {
    console.log(data[i].value);
}

Answer 1

您可以使用Object.values和map：

const data = {"0":{"id":1,"value":"73.0","tracker_id":1,"created_at":"2020-05-04 20:13:22","updated_at":"2020-05-04 20:13:22"},"7":{"id":8,"value":"73.0","tracker_id":1,"created_at":"2020-05-03 20:13:22","updated_at":"2020-05-04 20:13:22"},"8":{"id":9,"value":"73.0","tracker_id":1,"created_at":"2020-05-06 19:48:31","updated_at":"2020-05-06 19:48:31"}}

const value = Object.values(data).map(e => e.value)

console.log(value)

Answer 2

应该有一个更好的解决方案，但它可以工作

const values = Object.values(json).map(({ value})  => value)

Answer 3

我想响应已经被解析了。如果您想像示例中那样遍历每个项目，

const result = Object.values(data);
for (i = 0; i < result.length; i++) {
           console.log(result[i].value);
    }

Answer 4

您可以使用 for循环来映射对象：

const data = {"0":{"id":1,"value":"72.0","tracker_id":1,"created_at":"2020-05-04 20:13:22","updated_at":"2020-05-04 20:13:22"},"7":{"id":8,"value":"73.0","tracker_id":1,"created_at":"2020-05-03 20:13:22","updated_at":"2020-05-04 20:13:22"},"8":{"id":9,"value":"74.0","tracker_id":1,"created_at":"2020-05-06 19:48:31","updated_at":"2020-05-06 19:48:31"}};

for (key in data) {
  console.log(data[key].value);
}

Answer 5

尝试一下：

Object.values(a).map(p => console.log(p.value));

从响应中获取特定值

5 个答案: