我无法使累加器的循环正常工作,并抛出错误Python

时间:2020-05-04 13:34:43

标签: python loops iteration accumulator

我正在尝试制作一个程序,让用户输入课程名称,编号,成绩和学分,以计算GPA和质量得分。我相信所有计算都是正确的,但是我不确定,因为我的循环中断了。我试图做一个循环,在该循环中累积迭代(ittNum),并将其与用户输入多少个类进行比较。基本上,我希望有一个循环,并且一旦用户输入了参加的课程数量,我的数据就可以返回到总计算中。

这是我最新的错误消息。

回溯(最近通话最近): 文件“ D:/Python/FinalProgram1.py”,第40行,在 ClassGPA() ClassGPA中的文件“ D:/Python/FinalProgram1.py”,第13行 ittNum = int('') ValueError:以10为底的int()无效文字:

#Ask user's input for total classes taken
classesTaken = int(input('How many classes did you take? '))

#set function to take inputs and do calculations, should return values
#to variables defined
def ClassGPA():
    courseNum = input('What was the course number? ')
    courseName = input('What was the name of the course? ')
    courseGrade = input('What was your letter grade? ')
    courseHour = int(input('How many credit hours was the course worth? '))
    ittNum = int('')
    if courseGrade == ('A'): numGrade = 4.00
    elif courseGrade == ('A-'): numGrade = 3.67
    elif courseGrade == ('B+'): numGrade = 3.33
    elif courseGrade == ('B'): numGrade = 3.00
    elif courseGrade == ('B-'): numGrade = 2.67
    elif courseGrade == ('C+'): numGrade = 2.33
    elif courseGrade == ('C'): numGrade = 2.00
    elif courseGrade == ('C-'): numGrade = 1.67
    elif courseGrade == ('D+'): numGrade = 1.33
    elif courseGrade == ('D'): numGrade = 1.00
    elif courseGrade == ('F'): numGrade = 0.00
    qualityPoints = (numGrade * courseHour)
    print('Course:', courseNum, ', Course Name:', courseName, ', Quality Points:',\
          qualityPoints, ', GPA:', numGrade)
    ittNum = ittNum + 1
    totalHour += courseHour
    totalQual += qualityPoints
    totalGPA += numGrade
#Set loop condition
    if ittNum <= classesTaken:
        ClassGPA()
    else:
        return totalHour
        return totalQual
        return totalGPA

ClassGPA()

GPA = (totalGPA / totalQual)
print('Your total Quality Points for the semester were ', sum(totalQual))
print('Your total GPA for the semester was ', GPA```

1 个答案:

答案 0 :(得分:0)

您的错误在这里: ittNum = int('')

您正在尝试将空字符串强制转换为int,但这无法完成。

编辑:

此代码还有很多其他问题。

  1. 这不是循环。相反,这是对递归的不当使用。
  2. 您的变量classesTaken从未声明或初始化。
  3. 此函数返回的值(如果有,请参见问题2)永远不会分配给任何东西。
  4. 您只能从函数返回一次。在第一个之后返回的两个项目将永远不会真正返回。
  5. 您似乎正在尝试使用返回变量totalGPAtotalQual,这种方式将永远无法工作,请参阅问题4。