Question

我有4个数组，如下所示

array1 = ["one", "two", "three"];
array2 = ["1", "2", "3"];
array3 = ["a", "b", "c"];
array4 = ["10", "20", "30"];

通过使用这些数组的元素，我需要创建如下的另一组数组

oneArray = ["one", "1", "a", "10"];
twoArray = ["two", "2", "b", "20"];
threeArray = ["three", "3", "c", "30"];

有没有简单的方法可以做到这一点？

Answer 1

使用lodash：

array1 = ["one", "two", "three"];
array2 = ["1", "2", "3"];
array3 = ["a", "b", "c"];
array4 = ["10", "20", "30"];

result = _.zip(array1, array2, array3, array

这应该给您：

[
  ["one", "1", "a", "10"],
  ["two", "2", "b", "20"],
  ["three", "3", "c", "30"]
]

Answer 2

是的，这很简单

const array1 = ["one", "two", "three"];
const array2 = ["1", "2", "3"];
const array3 = ["a", "b", "c"];
const array4 = ["10", "20", "30"];

const oneArray = [array1[0],array2[0],array3[0],array4[0]];
const twoArray = [array1[1],array2[1],array3[1],array4[1]];
const threeArray = [array1[2],array2[2],array3[2],array4[2]];
console.log([oneArray, twoArray, threeArray])

Answer 3

Caused by: org.xml.sax.SAXParseException: cvc-complex-type.3.1: La valeur '2.2' de l'attribut 'version' de l'?l?ment 'persistence' n'est pas valide au regard de l'utilisation de l'attribut correspondant. L'attribut 'version' doit avoir la valeur fixe de '2.1.

Answer 4

在一个数组中组合数组，并使用map。即使您的数组大小从3个元素增加到更多，这也应该起作用。

const array1 = ["one", "two", "three"];
const array2 = ["1", "2", "3"];
const array3 = ["a", "b", "c"];
const array4 = ["10", "20", "30"];

const all = [array1, array2, array3, array4];
const [oneArray, twoArray, threeArray] = all[0].map((_, i) => all.map(arr => arr[i]));

console.log(oneArray);
console.log(twoArray);
console.log(threeArray);

Answer 5

尝试此代码。它会解决您的问题。

<security:http auto-config="false" use-expressions="true" entry-point-ref="authEntryPoint" disable-url-rewriting="true">
    <security:intercept-url pattern="/" access="isAnonymous() or isAuthenticated()" />   
    <security:intercept-url pattern="/index.jsp" access="isAnonymous() or isAuthenticated()" /> 
    <security:intercept-url pattern="/another-url" access="isAnonymous() or isAuthenticated()" />
    ...
    <security:intercept-url pattern="/**" access="isAuthenticated()" />
</security:http>

使用其他数组中的元素创建一个新数组

5 个答案: