我正在将Parcelable
中的ArrayList<Contact>
对象从Activity1发送到Activity2。
在将对象实际发送到Activity2之前,我先执行简单的Log.i()
函数。它打印出以下内容:
I/String representation from Activity1: Contact{id=1, firstName='John', lastName='Doe', email='john@gmail.com', photoPath='/storage/emulated/0/Pictures/Screenshots/Screenshot_20200502-094346__02.jpg', note='some notes'}
在Activity2中,它打印出以下内容:
I/String representation from Activity2: Contact{id=6, firstName='1', lastName='John', email='Doe', photoPath='john@gmail.com', note='/storage/emulated/0/Pictures/Screenshots/Screenshot_20200502-094346__02.jpg'}
对象完全被弄乱了。 id不可能是6,因为我在db中只有一个对象。对于其他字段,您可以自己查看。
最后,这里是完整的Contact
类:
public class Contact implements Parcelable{
@SerializedName("id")
@Expose
private Integer id;
@SerializedName("firstName")
@Expose
private String firstName;
@SerializedName("lastName")
@Expose
private String lastName;
@SerializedName("email")
@Expose
private String email;
@SerializedName("photoPath")
@Expose
private String photoPath;
@SerializedName("note")
@Expose
private String note;
public Contact(){
//photoPath = "";
}
public Contact(Integer id, String firstName, String lastName, String email, String photoPath, String note) {
this.id = id;
this.firstName = firstName;
this.lastName = lastName;
this.email = email;
this.photoPath = photoPath;
this.note = note;
}
protected Contact(Parcel in) {
id = in.readInt();
firstName = in.readString();
lastName = in.readString();
email = in.readString();
photoPath = in.readString();
note = in.readString();
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getPhotoPath() {
return photoPath;
}
public void setPhotoPath(String photoPath) {
this.photoPath = photoPath;
}
public String getNote() {
return note;
}
public void setNote(String note) {
this.note = note;
}
public String getPhotoFilename() {
String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
// Log.i("timestampe", timeStamp);
return "IMG_" + getId() + "_" + timeStamp + ".jpg";
}
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeStringArray(new String[]{this.id.toString(), this.firstName, this.lastName, this.email, this.photoPath, this.note});
/*dest.writeString(this.id.toString());
dest.writeString(this.firstName);
dest.writeString(this.lastName);
dest.writeString(this.email);
dest.writeString(this.photoPath);
dest.writeString(this.note);*/
}
public static final Parcelable.Creator<Contact> CREATOR= new Parcelable.Creator<Contact>() {
@Override
public Contact createFromParcel(Parcel source) {
// TODO Auto-generated method stub
return new Contact(source); //using parcelable constructor
}
@Override
public Contact[] newArray(int size) {
// TODO Auto-generated method stub
return new Contact[size];
}
};
@Override
public String toString() {
return "Contact{" +
"id=" + id +
", firstName='" + firstName + '\'' +
", lastName='" + lastName + '\'' +
", email='" + email + '\'' +
", photoPath='" + photoPath + '\'' +
", note='" + note + '\'' +
'}';
}
}
我已经尝试了两个选项from writeToParcel()
,均无效。
答案 0 :(得分:1)
您的writeToParcel()
必须与您的Contact(Parcel in)
完全匹配:如果您使用的是readInt()
,则需要以完全相同的顺序使用writeInt()
。
答案 1 :(得分:0)
是的,伊恩,我确实喜欢你在评论中建议的。现在可以使用了。谢谢:)
protected Contact(Parcel in) {
id = in.readInt();
firstName = in.readString();
lastName = in.readString();
email = in.readString();
photoPath = in.readString();
note = in.readString();
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeInt(this.id);
dest.writeString(this.firstName);
dest.writeString(this.lastName);
dest.writeString(this.email);
dest.writeString(this.photoPath);
dest.writeString(this.note);
}