Question

我有lua脚本将英语布局重新绑定为西里尔字母，但是，当我在游戏中使用它时，每次按下绑定键都会导致微滞后。

lmc_assign_keyboard('MACROS');
lmc_set_handler('MACROS',function(button, direction)
  if (direction == 0) then return end
  if (button == string.byte('Q')) then lmc_send_input(0, 1081, 4)
  elseif (button == string.byte('A')) then lmc_send_input(0, 1092, 4)
  elseif (button == string.byte('W')) then lmc_send_input(0, 1094, 4)
  elseif (button == string.byte('S')) then lmc_send_input(0, 1099, 4)
  elseif (button == string.byte('E')) then lmc_send_input(0, 1091, 4)
  elseif (button == string.byte('D')) then lmc_send_input(0, 1074, 4)
  elseif (button == string.byte('R')) then lmc_send_input(0, 1082, 4)
  elseif (button == string.byte('F')) then lmc_send_input(0, 1072, 4)
  elseif (button == string.byte('T')) then lmc_send_input(0, 1077, 4)
  elseif (button == string.byte('G')) then lmc_send_input(0, 1087, 4)
  elseif (button == string.byte('Y')) then lmc_send_input(0, 1085, 4)
  elseif (button == string.byte('H')) then lmc_send_input(0, 1088, 4)
  elseif (button == string.byte('U')) then lmc_send_input(0, 1075, 4)
  elseif (button == string.byte('J')) then lmc_send_input(0, 1086, 4)
  elseif (button == string.byte('I')) then lmc_send_input(0, 1096, 4)
  elseif (button == string.byte('K')) then lmc_send_input(0, 1083, 4)
  elseif (button == string.byte('O')) then lmc_send_input(0, 1097, 4)
  elseif (button == string.byte('L')) then lmc_send_input(0, 1076, 4)
  elseif (button == string.byte('P')) then lmc_send_input(0, 1079, 4)
  elseif (button == string.byte(';')) then lmc_send_input(0, 1078, 4)
  elseif (button == string.byte("'")) then lmc_send_input(0, 1101, 4)
  end
end)

有没有办法改善此脚本的性能？

Answer 1

有许多对string.byte的调用，这些调用本质上是常量。因此，将其排除在外。还可以使用表而不是ifs链。看到以下代码：

local T={
    [string.byte('Q')]=1081,
    [string.byte('A')]=1092,
    [string.byte('W')]=1094,
    [string.byte('S')]=1099,
    [string.byte('E')]=1091,
    [string.byte('D')]=1074,
    [string.byte('R')]=1082,
    [string.byte('F')]=1072,
    [string.byte('T')]=1077,
    [string.byte('G')]=1087,
    [string.byte('Y')]=1085,
    [string.byte('H')]=1088,
    [string.byte('U')]=1075,
    [string.byte('J')]=1086,
    [string.byte('I')]=1096,
    [string.byte('K')]=1083,
    [string.byte('O')]=1097,
    [string.byte('L')]=1076,
    [string.byte('P')]=1079,
    [string.byte(';')]=1078,
    [string.byte("'")]=1101,
}

lmc_assign_keyboard('MACROS');
lmc_set_handler('MACROS',function(button, direction)
  if (direction == 0) then return end
  if T[button] then lmc_send_input(0,T[button],4) end
end)

有没有一种方法可以减轻Lua脚本的负担？

1 个答案: