Question

因此，我有一个名为“产品”的数组，其中包含对象，并且每个对象都有唯一的ID。我还有另一个名为“ productsAdditionalInfo”的数组，其中包含与“ products”有关的其他信息，每个对象都有一个owner_id，该owner_id与“ products”数组中的一个对象匹配。 “ productsAdditionalInfo”在一个数组内可能有许多对象，但相对于该数组，总是具有相同的owner_id。

我正在尝试遍历'productsAdditionalInfo'数组以获取'owner_id'并将其与products数组中的'id'匹配，然后将名称空间添加为键，并将值添加为值，然后将其返回为新数组。但是，似乎我遇到了第一个障碍。我在控制台中获得“ Duration”的第一个键，然后得到未定义的“名称空间”。

我希望这是有意义的，如果没有的话，我已经举了一个关于应该如何做的例子。感谢您的帮助。

编辑：有人建议这与another question类似/相同，在这里您将它们合并在一起，但是我相信我的问题有所不同，因为我没有完全将它们仅仅合并到某些信息中。

let products = [ {id: 102, type: "toy"}, {id: 245, type: "food"}, {id: 312, type: "clothes"} ]

let productsAdditionalInfo = [ 
  [{namespace: "Duration", value: 5, owner_id: 245}, {namespace: "effect", value: "Tail", owner_id: 245}], 
  [{namespace: "Supplier", owner_id: 312, value: "rev"}], 
  [{namespace: "amount", value: 0, owner_id: 102}, {namespace: "effect", value: "plush", owner_id: 102}] 
]

$.each(productsAdditionalInfo, function( index, product ) {
  console.log( product[index].namespace );
});


// let whatItShouldBe = [ {id: 102, type: "toy", amount: 0, effect: "plush" }, {id: 245, type: "food", Duration: 5, effect: "Tail"}, {id: 312,  type: "clothes", Supplier: "rev"} ]

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

Answer 1

一种实现此目的的方法是遍历每个产品，并基于productAdditionsInfo检索关联的owner_id。在这里，您可以从添加项中创建一个对象，并将两者合并在一起，如下所示：

let products = [{id: 102, type: "toy"}, {id: 245, type: "food"}, {id: 312, type: "clothes"}]
let productsAdditionalInfo = [ 
  [{namespace: "Duration", value: 5, owner_id: 245}, {namespace: "effect", value: "Tail", owner_id: 245}], 
  [{namespace: "Supplier", owner_id: 312, value: "rev"}], 
  [{namespace: "amount", value: 0, owner_id: 102}, {namespace: "effect", value: "plush", owner_id: 102}] 
]

let merged = products.map(p => {
  var info = productsAdditionalInfo.filter(i => i[0].owner_id == p.id)[0].map(i => ({ [i.namespace]: i.value }));
  info.push(p);
  return Object.assign(...info);
});

console.log(merged);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

这假设productsAdditionalInfo中的第二级数组总是由同一owner_id分组。

Answer 2

let products = [ {id: 102, type: "toy"}, {id: 245, type: "food"}, {id: 312, type: "clothes"} ]

let productsAdditionalInfo = [ 
  [{namespace: "Duration", value: 5, owner_id: 245}, {namespace: "effect", value: "Tail", owner_id: 245}], 
  [{namespace: "Supplier", owner_id: 312, value: "rev"}], 
  [{namespace: "amount", value: 0, owner_id: 102}, {namespace: "effect", value: "plush", owner_id: 102}] 
]

const flatPAI = productsAdditionalInfo.flat();

console.log(
products.map( p => 
  Object.assign(p,
    ...flatPAI.filter(
         info => info.owner_id == p.id
       ).map(
         info => ({[info.namespace]: info.value})))
)
);



// let whatItShouldBe = [ {id: 102, type: "toy", amount: 0, effect: "plush" }, {id: 245, type: "food", Duration: 5, effect: "Tail"}, {id: 312,  type: "clothes", Supplier: "rev"} ]

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

遍历数组数组中的每个对象找到ID，将其与数组中的另一个对象匹配并将它们连接在一起

2 个答案: