我正在循环遍历此数组,我希望每个数组对象都获得随机颜色,但是它一直在将i添加在getRandomColor()后面,而不是添加到变量中。
所以它最终像例如#0A60860 + i
那是为什么?
我的app.js
function getRandomColor() {
return "#" + Math.random().toString(16).slice(2,8);
}
let randomcolor = getRandomColor()
let randomcolor0 = getRandomColor()
let randomcolor1 = getRandomColor()
let randomcolor2 = getRandomColor()
let randomcolor3 = getRandomColor()
let randomcolor4 = getRandomColor()
let randomcolor5 = getRandomColor()
let randomcolor6 = getRandomColor()
let randomcolor7 = getRandomColor()
let randomcolor8 = getRandomColor()
let randomcolor9 = getRandomColor()
let randomcolor10 = getRandomColor()
var items = [{id: 24550986,username: "addwell",matchmaking_group_id: 5378563},{id: 30168682,username: "ekkelito",matchmaking_group_id: 5378563},{id: 41526903,username: "dkMrGOD",matchmaking_group_id: 5373230},{id: 87892435,username: "FluffyBunny",matchmaking_group_id: 5373230},{id: 115472481,username: "hinter",matchmaking_group_id: 5378563},{id: 290200108,username: "Jonatan",matchmaking_group_id: 5376993},{id: 296745880,username: "Joy",matchmaking_group_id: 5376993},{id: 352928851,username: "DiktatorN",matchmaking_group_id: 5376993},{id: 932540677,username: "MIKEEEEEEY",matchmaking_group_id: 5378560},{id: 1030322875,username: "fknbr0r",matchmaking_group_id: 5377517}],
keys = { matchmaking_group_id: 'sections', username: 'items' }, // or more if required
result = [],
temp = { _: result };
items.forEach(function (object) {
Object.keys(keys).reduce(function (level, key) {
if (!level[object[key]]) {
level[object[key]] = { _: [] };
level._.push({ [key]: object[key], [keys[key]]: level[object[key]]._ });
}
return level[object[key]];
}, temp)._.push({ title: object.title, description: object.description });
});
var arrayLength = result.length;
for (var i = 0; i < arrayLength; i++) {
console.log(result[i]);
console.log(i)
randomcolor = randomcolor + i;
var arrayLengthsections = result[i].sections.length;
for (var ii = 0; ii < arrayLengthsections; ii++) {
console.log(result[i].sections[ii].username)
$( `span:contains('${result[i].sections[ii].username}')` ).css("border", '1px solid ' + randomcolor)
console.log(randomcolor)
}
}
答案 0 :(得分:1)
我看到很多不适合使用这段代码的东西,但我假设您是一个初学者。
首先,这不是一个数组,它们只是多个变量。
let randomcolor = getRandomColor()
let randomcolor0 = getRandomColor()
let randomcolor1 = getRandomColor()
let randomcolor2 = getRandomColor()
let randomcolor3 = getRandomColor()
let randomcolor4 = getRandomColor()
let randomcolor5 = getRandomColor()
let randomcolor6 = getRandomColor()
let randomcolor7 = getRandomColor()
let randomcolor8 = getRandomColor()
let randomcolor9 = getRandomColor()
但是它会一直在getRandomColor()后面添加i而不是添加到变量中。
您不能像这样通过“命名”来访问变量:
randomcolor = randomcolor + i;
您应该创建一个array,有很多方法可以在javascript中创建数组(创建一个空数组,然后在其中添加值,创建一个已填充的数组,等等)
const randomColors = [
getRandomColor(),
getRandomColor(),
getRandomColor(),
getRandomColor(),
];
这将创建一个包含4个值的数组。这种语法称为“文字数组”,有关数组,请参见this answer
然后您使用randomColors[i]
但是据我所知,您甚至不需要预先创建这些颜色然后存储,您可以:
for (let ii = 0; ii < arrayLengthsections; ii++) {
$( `span:contains('${result[i].sections[ii].username}')` )
.css("border", '1px solid ' + getRandomColor())
}
答案 1 :(得分:0)
请考虑以下示例。
$(function() {
function getRandomColor() {
return "#" + Math.random().toString(16).slice(2, 8);
}
function drawContent(data) {
$.each(data, function(i, el) {
$("<span>").html(el.username).appendTo($(".content"));
});
}
var items = [{
id: 24550986,
username: "addwell",
matchmaking_group_id: 5378563
}, {
id: 30168682,
username: "ekkelito",
matchmaking_group_id: 5378563
}, {
id: 41526903,
username: "dkMrGOD",
matchmaking_group_id: 5373230
}, {
id: 87892435,
username: "FluffyBunny",
matchmaking_group_id: 5373230
}, {
id: 115472481,
username: "hinter",
matchmaking_group_id: 5378563
}, {
id: 290200108,
username: "Jonatan",
matchmaking_group_id: 5376993
}, {
id: 296745880,
username: "Joy",
matchmaking_group_id: 5376993
}, {
id: 352928851,
username: "DiktatorN",
matchmaking_group_id: 5376993
}, {
id: 932540677,
username: "MIKEEEEEEY",
matchmaking_group_id: 5378560
}, {
id: 1030322875,
username: "fknbr0r",
matchmaking_group_id: 5377517
}];
console.log("items", items);
drawContent(items);
$.each(items, function(i, obj) {
console.log("-Needle: " + obj.username);
$(".content > span").each(function(j, el) {
console.log("--Stack: " + $(el).text());
if ($(el).text().indexOf(obj.username) == 0) {
$(el).css("border", '1px solid ' + getRandomColor());
console.log("---Hit^: " + $(el).attr("style"));
}
});
});
});
.content span {
display: inline-block;
padding: 2px;
margin-right: 3px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="content"></div>
如果返回一个String并连接一个Integer,它将不会添加它,而是会附加到String上。例如其中i
是1
,#0A60860 + i
是#0A608601
,而不是#0A60861
。对于正确的颜色代码来说,这也是太多字符。 #0A6086
,#000000
和#FFFFFF
是正确的。