class mca1
{
public:
void power(float m,int n)
{
cout<<"RESULT OF "<<m<<"^"<<n<<"="<<pow(m,n);
}
};
class mca2:public mca1
{
public:
void power(int m,int n)
{
cout<<"\nRESULT OF "<<m<<"^"<<n<<"="<<pow(m,n);
}
};
请告诉我,有什么方法可以不使用虚函数而仅在参数的基础上调用覆盖函数?
答案 0 :(得分:0)
您可以将基类函数拉入派生类范围,使其表现为重载函数。
class mca1
{
public:
void power(float m,int n)
{
cout<<"RESULT OF "<<m<<"^"<<n<<"="<<pow(m,n);
}
};
class mca2:public mca1
{
public:
using mca1::power;
void power(int m,int n)
{
cout<<"\nRESULT OF "<<m<<"^"<<n<<"="<<pow(m,n);
}
};