Question

我有一个查询，可以按周提取数据并将其分组在一起。但是我没有显示没有数据的星期。我想显示所有星期，即使他们没有空值

这是一个查询，如果有人可以帮助我，这会很棒

SELECT 
    DATEADD (week, datediff(week, 0, StartDate), -1) as 'WeekOf'
   ,DATEADD (week, datediff(week, 0, StartDate), +5) as 'to'
   ,DATEPART(wk, StartDate) as 'WeekNumber'

FROM [DESOutage].[dbo].[OPSInterruption]

Where  StartDate > '2020-01-01' and EndDate <'2020-02-01' 

Group by DATEADD (week, datediff(week, 0, StartDate), -1),DATEPART(wk, StartDate),DATEADD (week, datediff(week, 0, StartDate), +5)

***************输出*************** 如您所见，由于没有返回数据，因此第2和第4周丢失了。我仍然希望在输出中看到第2周和第4周的结果可能是0。

WeekOf至WeekNumber 2019-12-29 00：00：00.000 2020-01-04 00：00：00.000 1 2020-01-12 00：00：00.000 2020-01-18 00：00：00.000 3 2020-01-26 00：00：00.000 2020-02-01 00：00：00.000 5

Answer 1

您可能需要一个日历表。这是一种生成未经测试的代码实现的快速方法。我假设StartDate可能包含时间成分，因此需要合并日期。

DECLARE @StartYear DATETIME = '20200101'
DECLARE @days      INT      = 366

;WITH
  E1(N) AS (
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
  ),                                   -- 1*10^1 or 10 rows
  E2(N) AS (SELECT 1 FROM E1 a, E1 b), -- 1*10^2 or 100 rows
  E4(N) AS (SELECT 1 FROM E2 a, E2 b), -- 1*10^4 or 10,000 rows
  E8(N) AS (SELECT 1 FROM E4 a, E4 b), -- 1*10^8 or 100,000,000 rows
  Tally(N) AS (SELECT TOP (@Days) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E8),
  Calendar AS (
    SELECT  StartOfDay = DATEADD(dd,N-1,@StartYear),
            EndOfDay   = DATEADD(second, -1, DATEADD(dd,N  ,@StartYear))
    FROM Tally)

SELECT  DATEADD (week, datediff(week, 0, COALESCE(x.StartDate, c.StartOfDay) ), -1) as 'WeekOf'
      , DATEADD (week, datediff(week, 0, COALESCE(x.StartDate, c.StartOfDay)), +5) as 'to'
      , DATEPART(wk, COALESCE(x.StartDate, c.StartOfDay)) as 'WeekNumber'
FROM    Calendar c
        INNER JOIN [DESOutage].[dbo].[OPSInterruption] x
                ON x.StartDate > c.StartOfDay AND x.StartDate <= c.EndOfDay
WHERE   c.StartOfDay > '2020-01-01' AND c.StartOfDay <'2020-02-01' 
GROUP BY DATEADD (week, datediff(week, 0, COALESCE(x.StartDate, c.StartOfDay)), -1),
         DATEPART(wk, COALESCE(x.StartDate, c.StartOfDay)),
         DATEADD (week, datediff(week, 0, COALESCE(x.StartDate, c.StartOfDay)), +5)

即使没有数据也显示一年中的每个星期

1 个答案: