Question

有效的电子邮件格式：word_character@word_character.word_character ..

我尝试过使用(\b\w+\b@\b\w+\b\.\b\w+\b)正则表达式，但它仅与第一个匹配：

代码：

public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        Pattern p = Pattern.compile("(\b\w+\b@\b\w+\b\.\b\w+\b)");
        String s= "";
        while (t-- > 0) {
            s += in.next();
        }
        Matcher m = p.matcher(s);
        int count = 0;
        while (m.find()) {
            count++;
        }
        System.out.println(count);
    }

输入：

1

a1@gmail.com b1@gmail.com c1@gmail.com

Output: 1

Expected output: 3

Answer 1

您没有在添加空间来分隔电子邮件。

执行以下操作：

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        System.out.print("How many emails do you want to enter?: ");
        int t = in.nextInt();
        Pattern p = Pattern.compile("(\\b\\w+@\\w+\\.\\w+\\b)");
        String s = "";
        while (t-- > 0) {
            s += in.next() + " "; // Add space here
        }
        Matcher m = p.matcher(s);
        int count = 0;
        while (m.find()) {
            count++;
        }
        System.out.println(count);
    }
}

示例运行：

How many emails do you want to enter?: 3
a1@gmail.com b1@gmail.com c1@gmail.com
3

正则表达式仅匹配首次出现

1 个答案: