我正在客户端使用ASP.NET和jQuery。
我正在使用Json.NET来序列化服务器端数据库中的数据,并在Ajax请求到达时将其发送到客户端。
当我打开FireBug时,我看到以下json:
{"d":"[\r\n {\r\n \"CategoryID\": 1,\r\n \"CategoryName\": \"a\",\r\n \"Description\": \"123\",\r\n \"CategoryType\": \"Personal\",\r\n \"Traits\": [\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n },\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n }\r\n ]\r\n },\r\n {\r\n \"CategoryID\": 1,\r\n \"CategoryName\": \"b\",\r\n \"Description\": \"bla bla\",\r\n \"CategoryType\": \"Professional\",\r\n \"Traits\": [\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n },\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n }\r\n ]\r\n },\r\n {\r\n \"CategoryID\": 1,\r\n \"CategoryName\": \"c\",\r\n \"Description\": \"123\",\r\n \"CategoryType\": \"Personal\",\r\n \"Traits\": [\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n },\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n }\r\n ]\r\n },\r\n {\r\n \"CategoryID\": 1,\r\n \"CategoryName\": \"d\",\r\n \"Description\": \"bla bla\",\r\n \"CategoryType\": \"Professional\",\r\n \"Traits\": [\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n },\r\n {\r\n \"TraitID\": 1,\r\n \"TraitName\": \"a\",\r\n \"Description\": \"aaa\"\r\n }\r\n ]\r\n }\r\n]"}
我的服务器端代码:
[WebMethod]
public static string LoadRatingForm()
{
bll_Trait t1 = new bll_Trait();
t1.TraitID = 1;
t1.TraitName = "a";
t1.Description = "aaa";
bll_Trait t2 = new bll_Trait();
t2.TraitID = 1;
t2.TraitName = "a";
t2.Description = "aaa";
bll_Trait t3 = new bll_Trait();
t3.TraitID = 1;
t3.TraitName = "a";
t3.Description = "aaa";
bll_Trait t4 = new bll_Trait();
t4.TraitID = 1;
t4.TraitName = "a";
t4.Description = "aaa";
bll_Category c1 = new bll_Category();
c1.CategoryID = 1;
c1.CategoryName = "a";
c1.CategoryType = "Personal";
c1.Description = "123";
c1.Traits.Add(t1);
c1.Traits.Add(t2);
bll_Category c2 = new bll_Category();
c2.CategoryID = 1;
c2.CategoryName = "b";
c2.CategoryType = "Professional";
c2.Description = "bla bla";
c2.Traits.Add(t3);
c2.Traits.Add(t4);
bll_Category c3 = new bll_Category();
c3.CategoryID = 1;
c3.CategoryName = "c";
c3.CategoryType = "Personal";
c3.Description = "123";
c3.Traits.Add(t1);
c3.Traits.Add(t2);
bll_Category c4 = new bll_Category();
c4.CategoryID = 1;
c4.CategoryName = "d";
c4.CategoryType = "Professional";
c4.Description = "bla bla";
c4.Traits.Add(t3);
c4.Traits.Add(t4);
List<bll_Category> list = new List<bll_Category>();
list.Add(c1);
list.Add(c2);
list.Add(c3);
list.Add(c4);
return JsonConvert.SerializeObject(list, Formatting.Indented);
}
我的jQuery代码:
$.ajax({
type: "POST",
url: "MyProfile.aspx/LoadRatingForm",
data: "{}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (response) {
var html;
var categories = response.d;
$.each(categories, function (i, category) {
// create
//while (category.CategoryType == "Professional") {
//
//}
html += category.CategoryName + " ";
});
dialog.append(html);
},
error: function () {
alert("ERROR");
}
});
'dialog'变量是一个jQuery UI模式对话框,$ .ajax代码位于对话框的'open'事件处理程序中......
如果没有'\ n','\ r'和'\',我应该怎样做才能使序列化结果成为“正确”的json格式?
提前致谢!
答案 0 :(得分:9)
您不应手动JSON序列化该列表。
当您通过POST调用并使用内容类型application/json
时,ASP.NET已经自动为您执行此操作。所以,你最终会得到一个双重序列化的响应,这就是为什么你发现你需要在jQuery已经解析过一次之后再次解析它。
如果您使用返回类型的List并直接返回列表,那么您应该处于良好状态。
更多信息:http://encosia.com/2011/04/13/asp-net-web-services-mistake-manual-json-serialization/
答案 1 :(得分:7)
您可以尝试return JsonConvert.SerializeObject(list, Formatting.None);
您是否看过这个相关问题ASP.NET+jQuery, how to deSerialize JSON?。可能与Content-Type标题有关。
编辑:看到评论,没有解析JSON。
答案 2 :(得分:1)
根据JSON规范:“可以在任何一对令牌之间插入空格。”
所以不要担心。
或者在这里阅读有关JSON格式的http://james.newtonking.com/projects/json/help/ReducingSerializedJSONSize.html