Question

我想在api响应中进行数据过滤。即做出这样的地址

/api/v1//CoinCost/full?coin_id=coin_name&dateStart=2020-02-06T00:00:00&dateEnd=2020-02-08T00:00:00

现在我有这个网址

/api/v1/CoinCost/

并且不进行过滤。

我的代码：

views.py

class CoinCostViewSet(viewsets.ViewSet):

    def list(self, request):
        queryset = Coins.objects.all()
        serializer = CoinSerializer(queryset, many=True)
        return Response(serializer.data)

urls.py

router = DefaultRouter()
router.register('CoinCost', CoinCostViewSet, basename='Coins')

urlpatterns = [
    path('', include(router.urls)),
    ]

serializers.py

class CoinCostsSerializer(serializers.ModelSerializer):
class Meta:
    fields = ('coin_id', 'crr', 'volume', 'reserve', 'price', 'timestamp')
    model = CoinCost

models.py

class CoinCost(models.Model):
coin_id = models.ForeignKey(Coins, on_delete=models.CASCADE)
crr = models.CharField(max_length=3)
volume = models.DecimalField(max_digits=19, decimal_places=4)
reserve = models.DecimalField(max_digits=19, decimal_places=4)
price = models.DecimalField(max_digits=19, decimal_places=4)
timestamp = models.DateTimeField(auto_now_add=True, blank=True)

请帮助进行必要的过滤。获取过滤网址。我已经坐了两天，我听不懂。我学习了很多文档，并尝试了一周的不同方法。但是没有帮助。谢谢！

Answer 1

我建议使用django_filters。您需要完成安装和设置部分。但是您的代码应如下所示。筛选字段可能与您想要的不同。如果这是硬性要求，则可以查看文档以了解如何更改参数名称。

我还修复了CoinCostViewSet与CoinCost而不是Coins相关的模型和序列化器。

from django_filters import rest_framework as filters

class CoinCostFilterSet(filters.FilterSet)
    class Meta:
        model = CoinCost
        fields = {
            'coin_id': ['exact'],
            'timestamp': ['gt', 'lt'],
        }

class CoinCostViewSet(viewsets.ViewSet):
    queryset = CoinCost.objects.all()
    serializer_class = CoinCostsSerializer
    filter_backends = (filters.DjangoFilterBackend,)
    filterset_class = CoinCostFilterSet

Answer 2

据我所知，您想要通过URL传递参数，并且您想要过滤器。我对您的Model不太了解，但是您可以使用Model.objects.filter（）进行过滤并将其序列化，然后将其作为JSON数据返回。我通过了过滤部分，只是写过有关从url获取查询参数的信息。

from rest_framework.views import APIView
from rest_framework import status


class CoinApiView(APIView):
    def get(self, request, *args, **kwargs):
        query_params = request.query_params
        coin_id = query_params.get('coin_id', None)
        date_start = query_params.get('dateStart', None)
        date_end = query_params.get('dateEnd', None)

        # if you need date_obj from string
        # date_obj = datetime.fromisoformat(date_start)
        print(coin_id)
        print(date_start)
        print(date_end)
        # In Response you can return anyting For ex: Response({'coins': ['Coin1', 'Coin2', ..], status=status.HTTP_200_OK})
        return Response(status.HTTP_200_OK)

具有viewset-router查询集过滤器的Django REST Framework

2 个答案: