Question

我正在尝试使用Tornado发出同步请求。
尝试进行API调用。

main.py

import tornado.web
import tornado.httpserver
import tornado.options
import tornado.ioloop
from tornado.web import url

from handlers import IndexHandler

from tornado.options import define, options
define("port", default=8000, help="run on the given port", type=int)

if __name__ == "__main__":
    tornado.options.parse_command_line()
    app = tornado.web.Application(
        handlers=[
            url(r"/", IndexHandler),
        ]
    )
    http_server = tornado.httpserver.HTTPServer(app)
    http_server.listen(options.port)
    tornado.ioloop.IOLoop.instance().start()

我的handlers.py是...

import tornado.web
import tornado.httpclient

import urllib
import json
import datetime
import time

class IndexHandler(tornado.web.RequestHandler):
    def get(self):
        query = self.get_argument('q')
        client = tornado.httpclient.HTTPClient()
        response = client.fetch("https://pokeapi.co/api/v2/pokemon/" + urllib.urlencode(("query")))
        print(response)
        if response == "Not Found":
            self.write("Invalid Input")
        response_data = json.loads(response.body)
        pikachu_name = response_data['name']
        pikachu_order = response_data['order']
        self.write("""
            Pickachu Name: %s <br>
            Pickachu Order: %d <br>
            """ %(pikachu_name, pikachu_order))

现在我面临的问题是

[E 200407 02:18:37 web:1792] Uncaught exception GET /?q=pikachu (::1)
    HTTPServerRequest(protocol='http', host='localhost:8000', method='GET', uri='/?q=pikachu', version='HTTP/1.1', remote_ip='::1')
    Traceback (most recent call last):
      File "C:\Python\Python37\lib\site-packages\tornado\web.py", line 1701, in _execute
        result = method(*self.path_args, **self.path_kwargs)
      File "C:\Users\Bagga\Documents\tornado\Tweet Rate\handlers.py", line 12, in get
        client = tornado.httpclient.HTTPClient()
      File "C:\Python\Python37\lib\site-packages\tornado\httpclient.py", line 107, in __init__
        self._async_client = self._io_loop.run_sync(make_client)
      File "C:\Python\Python37\lib\site-packages\tornado\ioloop.py", line 526, in run_sync
        self.start()
      File "C:\Python\Python37\lib\site-packages\tornado\platform\asyncio.py", line 149, in start
        self.asyncio_loop.run_forever()
      File "C:\Python\Python37\lib\asyncio\base_events.py", line 529, in run_forever
        'Cannot run the event loop while another loop is running')
    RuntimeError: Cannot run the event loop while another loop is running
[E 200407 02:18:37 web:2250] 500 GET /?q=pikachu (::1) 55.85ms

问题是什么，我该如何解决？
我在这里看到的主要错误是，
RuntimeError：当另一个循环正在运行时，无法运行事件循环
我认为这是由于IOLoop和HTTPClient引起的，但无法理解是什么问题？

Answer 1

我引用了documentation of HTTPClient

版本5.0中的更改：由于asyncio中的限制，在IOLoop运行时，不再可以使用同步HTTPClient。请改用AsyncHTTPClient。

请改为使用AsyncHTTPClient。

使用龙卷风发出同步请求。 RuntimeError：当另一个循环正在运行时，无法运行事件循环

1 个答案: