Question

每次我运行旨在构建弱Ai平台的代码时，都会收到 AttributeError：'NoneType'对象没有属性'lower'，而且我完全不知道为什么会这样在我正在关注的教程中工作正常。有人可以指导我修复此问题，因为我对python来说还很陌生。谢谢

import pyttsx3
import speech_recognition as sr
import datetime
import wikipedia
import webbrowser
import os
import smtplib
import pythoncom

print("Initializing Bot")

MASTER = "Bob"

engine = pyttsx3.init('sapi5')
voices = engine.getProperty('voices')
engine.setProperty('voice', voices[1].id)

def speak(text):
    engine.say(text)
    engine.runAndWait()


def wishMe():
    hour = int(datetime.datetime.now().hour)

    if hour>=0 and hour <12:
        speak("Good Morning" + MASTER)

    elif hour>=12 and hour<18:
        speak("Good Afternoon" + MASTER)
    else:
        speak("Good Evening" + MASTER)


    speak("How may I assist you?")

def takeCommand():
    r = sr.Recognizer()
    with sr.Microphone() as source:
        print("Listening...")
        audio = r.listen(source)
    try :
        print("Recognizing...")
        query = r.recognize_google(audio, language ='en-in')
        print(f"user said: {query}\n")

    except Exception as e:
        print("Sorry i didn't catch that...")

speak("Initializing bot...")
wishMe()
    query = takeCommand()

#Logic

if 'wikipedia' in query.lower():
    speak('Searching wikipedia...')
    query = query.replace("wikipedia", "")
    results = wikipedia.summary(query, sentences =2)
    print(results)
    speak(results)


if 'open youtube' in query.lower():
    webbrowser.open("youtube.com")

或者，麦克风也没有接听输入，为什么会出现这种情况？

Answer 1

该错误是因为变量query有时是None。并且您正在对其应用.lower()函数，该函数仅适用于str类型的对象。

您可以通过将代码放入if循环中进行控制，该循环仅在查询变量中包含字符串时才运行。也许像这样：

wishMe()
query = takeCommand()

#Logic

if query:
    if 'wikipedia' in query.lower():
        speak('Searching wikipedia...')
        query = query.replace("wikipedia", "")
        results = wikipedia.summary(query, sentences =2)
        print(results)
        speak(results)


    if 'open youtube' in query.lower():
        webbrowser.open("youtube.com")

Answer 2

您的函数未返回任何内容。例如：

def takeCommand():
    r = sr.Recognizer()
    with sr.Microphone() as source:
        print("Listening...")
        audio = r.listen(source)
    try :
        print("Recognizing...")
        query = r.recognize_google(audio, language ='en-in')
        print(f"user said: {query}\n")

    except Exception as e:
        print("Sorry i didn't catch that...")
    return query

别忘了标记我的回答是否对您有帮助

Answer 3

我正在尝试帮助您，但是我没有您要做什么的背景，但我将举一个例子：

wishMe()
query = takeCommand()

#Logic

if query:
# an then you can check your condition
query.lower()

Answer 4

您需要添加takeCommand函数的返回类型...然后 query=takeCommand 函数可以正常工作，否则它会向您返回错误（无类型）因此，请在return query函数中添加takeCommand并尝试

我希望它将对您有帮助

谢谢

如何修复AttributeError：'NoneType'对象没有属性'lower'？

4 个答案: