Question

我写了一些代码来打印出输入到给定文本中所需数量的字母。由于某些原因，在9个字母之后，它似乎会增加1，并且会稍微超出输入中给出的字母数量。任何建议，不胜感激：）

// Libraries
#include <cs50.h>
#include <stdio.h>
#include <math.h>
#include <string.h>
#include <ctype.h>

// Function to count letters
int count_letter(string text)
{
    // Declaring function variables
    int lettercount = 0;
    int number_of_letters;
    int spaces = 0;
    int letter_all;

    // Getting length of the text
    number_of_letters = strlen(text);

    // Counting the letters in the text inputted
    for(lettercount = 0; lettercount < number_of_letters; lettercount++)
       {    // If text is from a-z then count the text
            if(isalpha(text[lettercount]))
                lettercount++;
            // If text is equal to space then add up the spaces
            else if(isspace(text[lettercount]))
                spaces++;
            // Minus the spaces from the lettercount
            letter_all = lettercount - spaces;
        }

    return letter_all;

}


int main(void)
{
    // Getting a string of Text and storing it in a variable
    string passage = get_string("text: ");
    {
        printf("%i letter(s)\n", count_letter(passage));

    }

}

Answer 1

当您执行letter_all = lettercount - spaces时，您要在字母数中减去空格数。因此，如果您使用字符串“ he llo”，则有5个字母和1个空格，并且您正在执行5-1。然后您的程序将打印4，这是不正确的。因此，您应该只打印出lettercount以获取字母编号。

这就是您的功能。

int count_letter(string text)
{
    // Declaring function variables
    int lettercount = 0;
    int number_of_letters;
    int spaces = 0;
    int letter_all,i;

    // Getting length of the text
    number_of_letters = strlen(text);
    // Counting the letters in the text inputted
    for(i = 0; i < number_of_letters; i++)
       {    // If text is from a-z then count the text
            if(isalpha(text[i]))
                lettercount++;
        }

    return lettercount;

}

Answer 2

在您的函数中，应删除此行letter_all = lettercount-减少实际字母数量的空格

// Libraries
#include <cs50.h>
#include <stdio.h>
#include <math.h>
#include <string.h>
#include <ctype.h>

int count_letter(string text)
{
    // Declaring function variables
    int lettercount = 0;
    int number_of_letters;
    int spaces = 0;
    int letter_all,i;

    // Getting length of the text
    number_of_letters = strlen(text);
    // Counting the letters in the text inputted
    for(i = 0; i < number_of_letters; i++)
       {    // If text is from a-z then count the text
            if(isalpha(text[i]))
                lettercount++;
        }

    return lettercount;

}
int main(void)
{
    // Getting a string of Text and storing it in a variable
    string passage = get_string("text: ");
    {
        printf("%i letter(s)\n", count_letter(passage));

    }

}

如何获得我的代码以打印正确的字母数？

2 个答案: