我问过this question here,我得到了satisfactory answer。但是我有一个新的问题无法解决。
我从query获得的输出是对象数组。如何将该数组转换为对象?我已经知道how to do it in plain javascript,但是如何在mongodb聚合查询中做到这一点?
您可以假定聚合查询中具有以下数据。
[
{ "choiceA": [
{"_id": ObjectId("..."), "voter": "Juzi", "choice": 0, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Juma", "choice": 0, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Jane", "choice": 0, "pollId": 100 },
]},
{ "choiceB": [
{"_id": ObjectId("..."), "voter": "Jamo", "choice": 1, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Juju", "choice": 1, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Jana", "choice": 1, "pollId": 100 }
]},
{ "choiceC": [ ] }
]
如何将其变成如下所示的对象
{
"choiceA": [
{"_id": ObjectId("..."), "voter": "Juzi", "choice": 0, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Juma", "choice": 0, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Jane", "choice": 0, "pollId": 100 },
],
"choiceB": [
{"_id": ObjectId("..."), "voter": "Jamo", "choice": 1, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Juju", "choice": 1, "pollId": 100 },
{"_id": ObjectId("..."), "voter": "Jana", "choice": 1, "pollId": 100 }
],
"choiceC": [ ]
}
或者您也可以将上面的结果作为输出来回答this question。谢谢。
答案 0 :(得分:1)
将以下步骤添加到您的管道中:
db.collection.aggregate([
{
$group: {
_id: null,
x: {
$push: "$$ROOT"
}
}
},
{
$project: {
_id: 0,
x: {
$mergeObjects: "$x"
}
}
},
{
$replaceRoot: {
newRoot: "$x"
}
}
])