Question

我有一个大注释栏，其中有一个单词NUMBER_OF_SERVERS_03，03可以是任意2位数字，也可以是n位数字，之后是数字，例如NUMBER_OF_SERVERS_03 2我想在此之后提取数字，例如< / p>

Notes Column - 'asdasd asdasda asdasd NUMBER_OF_SERVERS_03 24 hkashii rwnijt'
output will should be 24

谢谢拉克什

Answer 1

您需要将REGEXP_SUBSTR与匹配参数一起使用，如下所示：

SQL> SELECT
  2      REGEXP_SUBSTR('asdasd asdasda asdasd NUMBER_OF_SERVERS_03 24 hkashii rwnijt',
  3      'NUMBER_OF_SERVERS_[0-9]+\s+([0-9]+)', 1, 1, NULL, 1) as RESULT
  4  FROM
  5      DUAL;

RE
--
24

-- Example with spaces and different server number
SQL> SELECT
  2      REGEXP_SUBSTR('asdasd asdasda asdasd NUMBER_OF_SERVERS_11   10 hkashii rwnijt',
  3      'NUMBER_OF_SERVERS_[0-9]+\s+([0-9]+)', 1, 1, NULL, 1) as RESULT
  4  FROM
  5      DUAL;

RE
--
10

SQL>

干杯！

Answer 2

您可以使用regexp_replace()：

select regexp_replace(notes, '^.*NUMBER_OF_SERVERS_[0-9]+[^0-9]*([0-9]+).*$', '\1')
from (select 'asdasd asdasda asdasd NUMBER_OF_SERVERS_03 24 hkashii rwnijt' as notes from dual)

如果您知道数字在该字符串后跟一个空格，则可以将其简化为：

select regexp_replace(notes, '^.*NUMBER_OF_SERVERS_[0-9]+ ([0-9]+).*$', '\1')

从字符串中提取单词之后的单词

2 个答案: