我正在使用一个来自外部库的组件,该组件不允许我对其样式进行很多更改,但是我想更改作为材质ui按钮的按钮的样式,当检查该元素时,它清楚地显示了类 MuiButtonBase根MuiIconButton根MuiIconButton-colorInherit
例如,如何覆盖MuiIconButton根样式?这是我的组件:
class MyComponent extends Component {
render() {
const { classes } = this.props;
return (
<div className={classes.myComponent}>
<3rdPartyComponent />
</div>
);
}
}
export default withStyles(styles)(MyComponent)
我尝试如下声明样式功能,但没有成功:
const styles = theme => ({
myComponent: {
"&.MuiIconButton-root": {
padding: "0px"
}
}
});
有人可以帮助我吗?预先感谢。
答案 0 :(得分:4)
比方说,为myComponent
生成的类名称为myComponent-jss123
。您在样式(&.MuiIconButton-root
)中使用的选择器将与.myComponent-jss123.MuiIconButton-root
等效,该选择器将匹配具有以下两个类别的所有元素的元素。我相信您的意图是匹配应用div
类的myComponent
的后代的图标按钮。在这种情况下,您需要使用由空格表示的descendant combinator,因此适当的样式应如下所示:
const styles = theme => ({
myComponent: {
"& .MuiIconButton-root": {
padding: 0
}
}
});
这是一个完整的示例:
import React from "react";
import IconButton from "@material-ui/core/IconButton";
import DeleteIcon from "@material-ui/icons/Delete";
import { makeStyles } from "@material-ui/core/styles";
const useStyles = makeStyles({
myComponent: {
"& .MuiIconButton-root": {
padding: 0
}
}
});
const ThirdPartyComponent = () => {
return (
<div>
I'm a third party component that contains an IconButton:
<IconButton color="primary">
<DeleteIcon />
</IconButton>
</div>
);
};
export default function App() {
const classes = useStyles();
return (
<div className={classes.myComponent}>
<ThirdPartyComponent />
</div>
);
}
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