我正在做我的项目,我需要一些帮助。我在wordpress中创建自定义端点。除了一件事,一切都正常。我有数据库
| id | city | company | email | website
--------------------------------------------------------------
| 22 | city_1 | company one | comp@example.com | comp1.com
--------------------------------------------------------------
| 12 | city_2 | company two | comp2@example.com | comp2.com
--------------------------------------------------------------
| 31 | city_2 | company three | comp3@example.com | comp3.com
--------------------------------------------------------------
| 72 | city_3 | company four | comp4@example.com | comp4.com
我要打印包含该格式的JSON
{
"city":"city_1",
"companies": [
{
"id":"22",
"email":"comp@example.com",
"website":"comp1.com"
}
],
},
{
"city":"city_2",
"companies": [
{
"id":"12",
"email":"comp2@example.com",
"website":"comp2.com"
},
{
"id":"31",
"email":"comp3@example.com",
"website":"comp3.com"
}
],
},
{
"city":"city_4",
"companies": [
{
"id":"72",
"email":"comp4@example.com",
"website":"comp4.com"
}
],
},
因此,我想根据城市价值将多个值分组为一个。我该怎么做?我尝试使用GROUP BY语句,但它给了我一行。 我当前的SQL查询
SELECT * FROM database ORDER BY city COLLATE utf8_polish_ci
感谢您的帮助!
答案 0 :(得分:3)
使用
JSON_ARRAYAGG
select JSON_ARRAYAGG(JSON_OBJECT('city',city,'companies',companies)) from (
select city,JSON_ARRAYAGG(JSON_OBJECT('id',id,'company',
company,'email',email,'website',website)) as companies from test group by city
)t;
这将以JSON格式打印预期的输出。
输出:
[
{
"city": "city_1", "companies": [{"id": 22, "email": "comp@example.com ", "company": "company one ", "website": "comp1.com"}]
},
{
"city": "city_2", "companies": [{"id": 12, "email": "comp2@example.com", "company": "company two ", "website": "comp2.com"},
{"id": 31, "email": "comp3@example.com", "company": "company three", "website": "comp3.com"}]
}
]