我正在进行网络抓取,并且我在一个看起来像这样的json对象中获取了数据:
{'categories': '[{"title":"Name", "desc":"Mike"}, {"title":"Food", "desc":"Muffin"}]'}
我想遍历这本词典,只得到一个值“ Muffin”。 我的代码是:
for item in the_dict:
for i in range(0, len(item)-1):
muff_filter = json.loads(the_dict['categories'])[i]['title']
if muff_filter == 'Food':
print(json.loads(the_dict['categories'])[i]['desc'])
else:
pass
我得到了预期的输出,但是仍然出现错误:
Muffin
---------------------------------------------------------------------------------
IndexError Traceback (most recent call last)
<ipython-input-50-9a650257d42a> in <module>
61 for item in the_dict:
62 for i in range(0, len(item)-1):
---> 63 food_filter = json.loads(the_dict['categories'])[i]['title']
64 if food_filter == 'Food':
65 print(json.loads(the_dict['categories'])[i]['desc'])
IndexError: list index out of range
我尝试枚举列表,但仍然遇到相同的错误,并且还尝试使用键,值对但存在相同的错误。你能给我一个想法,我想错了吗?
+++因此,我根据注释中的建议运行了%xmode Verbose, 并且出现以下错误:
Muffin
--------------------------------------------------------------------------
IndexError Traceback (most recent call last)
<ipython-input-68-e1844b3cae82> in <module>
61 for item in get_cert:
62 for i in range(0, len(item)-2):
---> 63 the_dict= json.loads(the_dict['categories'])[i]['title']
global get_cert = {'categories': '[{"title":"Name","desc":"Mike"},{"title":"Food","desc":"Muffin"}]'}
global i = 2
64 if muff_filter == 'Food':
65 print(json.loads(the_dict['categories'])[i]['desc'])
IndexError: list index out of range
答案 0 :(得分:1)
如果您在the_dict
中有多个json数据大块,请遍历每个大块:
for jsondata in the_dict.values():
for d in json.loads(jsondata):
if d.get('title') == 'Food':
print(d['desc'])
或者如果您知道the_dict
中只有一个json数据,并且它在键'categories'
下:
for d in json.loads(the_dict['categories']):
if d.get('title') == 'Food':
print(d['desc'])
答案 1 :(得分:0)
for key, values in the_dict.items():
jvalues = json.loads(values)
for val in jvalues:
muff_filter = json.loads(val)['title']
if muff_filter == 'Food':
print(json.loads(val)['desc'])
else:
pass