我正在使用redis-semaphore gem版本0.3.1
。
由于某种原因,我有时无法释放陈旧的Redis锁。从我的分析看来,如果我的Docker进程在创建锁后崩溃,就会发生这种情况。
我在下面介绍了我的调试过程,并想知道是否有人可以建议如何进一步调试。
假设我们要使用以下名称创建一个redis锁:
name = "test"
我们将此变量插入两个不同的终端窗口中。首先,我们运行:
def lock_for_15_secs(name)
job = Redis::Semaphore.new(name.to_sym, redis: NonBlockingRedis.new(), custom_blpop: true, :stale_client_timeout => 15)
if job.lock(-1) == "0"
puts "Locked and starting"
sleep(15)
puts "Now it's stale, try to release in another process"
sleep(15)
puts "Now trying to unlock"
unlock = job.unlock
puts unlock == false ? "Wuhuu, already unlocked" : "Hm, should have been unlocked by another process, but wasn't"
end
end
lock_for_15_secs(name)
第二次运行:
def release_and_lock(name)
job = Redis::Semaphore.new(name.to_sym, redis: NonBlockingRedis.new(), custom_blpop: true, :stale_client_timeout => 15)
release = job.release_stale_locks!
count = job.available_count
puts "Release reponse is #{release.inspect} and available count is #{count}"
if job.lock(-1) == "0"
puts "Wuhuu, we can lock it"
job.unlock
else
puts "Hmm, we can't lock it"
end
end
release_and_lock(name)
通常会按预期播放。在15秒钟内,第二个终端无法释放锁定,但是在15秒钟后运行时,它将释放。以下是release_and_lock(name)
的输出。
在15秒之前:
irb(main):1:0> release_and_lock(name)
Release reponse is {"0"=>"1580292557.321834"} and available count is 0
Hmm, we can't lock it
=> nil
经过15秒后:
irb(main):2:0> release_and_lock(name)
Release reponse is {"0"=>"1580292557.321834"} and available count is 1
Wuhuu, we can lock it
=> 1
irb(main):3:0> release_and_lock(name)
Release reponse is {} and available count is 1
Wuhuu, we can lock it
但是只要我看到没有释放过时的锁,并且我运行release_and_lock(name)
进行诊断,就会返回此信息:
irb(main):4:0> release_and_lock(name)
Release reponse is {} and available count is 0
Hmm, we can't lock it
此时,我唯一的选择是刷新redis:
require 'non_blocking_redis'
non_blocking_redis = NonBlockingRedis.new()
non_blocking_redis.flushall
P.s。我的NonBlockingRedis
继承自Redis
:
class Redis
class Semaphore
def initialize(name, opts = {})
@custom_opts = opts
@name = name
@resource_count = opts.delete(:resources) || 1
@stale_client_timeout = opts.delete(:stale_client_timeout)
@redis = opts.delete(:redis) || Redis.new(opts)
@use_local_time = opts.delete(:use_local_time)
@custom_blpop = opts.delete(:custom_blpop) # false=queue, true=cancel
@tokens = []
end
def lock(timeout = 0)
exists_or_create!
release_stale_locks! if check_staleness?
token_pair = @redis.blpop(available_key, timeout, @custom_blpop)
return false if token_pair.nil?
current_token = token_pair[1]
@tokens.push(current_token)
@redis.hset(grabbed_key, current_token, current_time.to_f)
if block_given?
begin
yield current_token
ensure
signal(current_token)
end
end
current_token
end
alias_method :wait, :lock
end
end
class NonBlockingRedis < Redis
def initialize(options = {})
if options.empty?
options = {
url: Rails.application.secrets.redis_url,
db: Rails.application.secrets.redis_sidekiq_db,
driver: :hiredis,
network_timeout: 5
}
end
super(options)
end
def blpop(key, timeout, custom_blpop)
if custom_blpop
if timeout == -1
result = lpop(key)
return result if result.nil?
return [key, result]
else
super(key, timeout)
end
else
super
end
end
def lock(timeout = 0)
exists_or_create!
release_stale_locks! if check_staleness?
token_pair = @redis.blpop(available_key, timeout, @custom_blpop)
return false if token_pair.nil?
current_token = token_pair[1]
@tokens.push(current_token)
@redis.hset(grabbed_key, current_token, current_time.to_f)
if block_given?
begin
yield current_token
ensure
signal(current_token)
end
end
current_token
end
alias_method :wait, :lock
end
require 'non_blocking_redis'
答案 0 :(得分:1)
?很棒的错误?
我认为,如果您在SEMAPHORE:test:AVAILABLE
最可能在这里https://github.com/dv/redis-semaphore/blob/v0.3.1/lib/redis/semaphore.rb#L67
要复制
NonBlockingRedis.new.flushall
release_and_lock('test');
NonBlockingRedis.new.lpop('SEMAPHORE:test:AVAILABLE')
现在您最初拥有:
SEMAPHORE:test:AVAILABLE 0
SEMAPHORE:test:VERSION 1
SEMAPHORE:test:EXISTS 1
上面的代码之后,您将得到:
SEMAPHORE:test:VERSION 1
SEMAPHORE:test:EXISTS 1
代码检查SEMAPHORE:test:EXISTS
,然后期望具有SEMAPHORE:test:AVAILABLE
/ SEMAPHORE:test:GRABBED
通过我的简短检查,我认为不做修改就不可能使gem生效。我尝试添加expiration:
,但是以某种方式设法禁用了SEMAPHORE:test:EXISTS
NonBlockingRedis.new.ttl('SEMAPHORE:test:EXISTS') # => -1 and it should have been e.g. 20 seconds and going down
所以..也许会解决
class Redis
class Semaphore
def exists_or_create!
token = @redis.getset(exists_key, EXISTS_TOKEN)
if token.nil? || all_tokens.empty?
create!
else
# Previous versions of redis-semaphore did not set `version_key`.
# Make sure it's set now, so we can use it in future versions.
if token == API_VERSION && @redis.get(version_key).nil?
@redis.set(version_key, API_VERSION)
end
true
end
end
end
end
all_tokens为https://github.com/dv/redis-semaphore/blob/v0.3.1/lib/redis/semaphore.rb#L120
我不久将打开宝石的PR-> https://github.com/dv/redis-semaphore/pull/66也许?♂️
不确定如何使用NonBlockingRedis
,但是Redis::Semaphore
中没有使用它。您执行lock(-1)
,它在代码lpop
中进行。同样,代码也永远不会调用您的lock
。
这里是转储密钥的助手
class Test
def self.all
r = NonBlockingRedis.new
puts r.keys('*').map { |k|
[
k,
((r.hgetall(k) rescue r.get(k)) rescue r.lrange(k, 0, -1).join(' | '))
].join("\t\t")
}
end
end
> Test.all
SEMAPHORE:test:AVAILABLE 0
SEMAPHORE:test:VERSION 1
SEMAPHORE:test:EXISTS 1
为完整起见,这是您握住锁后的样子
SEMAPHORE:test:VERSION 1
SEMAPHORE:test:EXISTS 1
SEMAPHORE:test:GRABBED {"0"=>"1583672948.7168388"}