Question

  const displayCharacters =  async () => { 
    if(filteredCharacters !== 'default'){
      const a = filteredCharacters.map(e => e.name);
      const options = {
        method: "POST",
        headers: { "Content-Type": "application/json" },
        body: JSON.stringify({ 'data' : a })
      };

      const b = await fetch("/image",options).then(res => res.json())
      return b; 

    }else{
      return "yikes";
    }
  }


  console.log(displayCharacters());

我有这个获取请求，但是当我记录结果时，这就是我看到的：

Promise {<resolved>: "yikes"}
__proto__: Promise
[[PromiseStatus]]: "resolved"
[[PromiseValue]]: "yikes"

我只想要promiseValue而不是它周围的所有东西。我该怎么做呢？

Answer 1

async函数可立即返回承诺，而无需等待承诺解决。您可以改为在功能内使用console.log：

  const displayCharacters =  async () => { 
    if(filteredCharacters !== 'default'){
      const a = filteredCharacters.map(e => e.name);
      const options = {
        method: "POST",
        headers: { "Content-Type": "application/json" },
        body: JSON.stringify({ 'data' : a })
      };
      try {
        const b = await fetch("/image",options).then(res => res.json());
        console.log(b);

        //the better practice is however, to do like:
        const b = await fetch("/image",options)
        const result = await b.json(); 
        console.log(result );
      }
      catch(err) {
         console.log(err);
      }

    }else{
      console.log("yikes");
    }
  }


displayCharacters();

Answer 2

我知道使用访存的最佳方式是这样的：

const displayCharacters =  async () => { 
  if(filteredCharacters !== 'default'){
    const a = filteredCharacters.map(e => e.name);
    const options = {
      method: "POST",
      headers: { "Content-Type": "application/json" },
      body: JSON.stringify({ 'data' : a })
    };

    const b = await fetch("/image",options)
      .then(res => {
        // Handle API Errors
        if (!res.ok) {
          throw Error(res.statusText);
        }
        // Return if no errors
        return res.json();
      })
      // this is the data you want
      .then(data => data)
      // it will only reject on network failure or if anything prevented the request from completing
      .catch(error => {
        console.log(error.message)
      });

    return b; 

  }else{
    return "yikes";
  }
}

基本上，您将两个然后一个接点链接在一起，以完全理解响应 -第一个然后检查api级错误 -然后获取数据 -如果无法像连接问题那样到达api本身，则会调用catch

返回已解决的承诺值

2 个答案: