Question

我使用以下代码在_global.choiceMade等于1时补间动画片段...

onClipEvent (load) {
    import mx.transitions.Tween;
    import mx.transitions.easing.*; 
}

onClipEvent (enterFrame) {
if (_global.choiceMade == 1) {
    var myTweenX:Tween = new Tween(this, "_x", mx.transitions.easing.Back.easeOut, this._x, -349, 0.5, True);
}
}

这包含在主时间轴的每个帧中。它第一次运行正常，但在下一帧运行速度非常慢（大约12秒不是0.5并且非常不稳定），如果我然后返回第一帧并再次运行它，这次它非常慢。

我无法理解为什么它这样做我的CPU在运行时保持在6-15％左右，因此它不会太苛刻。

更新以显示我的其余代码：

在主时间轴上有一个框架，每个框架都包含一个动画片段。在每个动画片段的时间轴上包含：

//tint an object with a color just like Effect panel
//r, g, b between 0 and 255; amount between 0 and 100
Color.prototype.setTint = function(r, g, b, amount) {
var percent = 100-amount;
var trans = new Object();
trans.ra = trans.ga=trans.ba=percent;
var ratio = amount/100;
trans.rb = r*ratio;
trans.gb = g*ratio;
trans.bb = b*ratio;
this.setTransform(trans);
};//Robert Penner June 2001 - http://www.robertpenner.com
 MovieClip.prototype.scaleXY = function(to){
 this.onEnterFrame = function(){
 this._alpha = to-(to-this._alpha)/1.2;
 if(this._alpha > to-1 && this._alpha < to+1){
 this._alpha = to;
 delete this.onEnterFrame
 }
 }
 }
scoreUpdated = 0;
Answer = 1;
_global.choiceMade = 0;
Buttons = new Array(this.buttonHolder.True, this.buttonHolder.False);
Answers = new Array(this.Correct, this.Wrong);
for (i=0; i<Answers.length; i++) {
Answers[i]._alpha = 0;

}
for (b=0; b<Buttons.length; b++) {
Buttons[b].thisValue = b;

}

在这个动画片段中有两个动画片段按钮（True和False），其中包含以下代码：

onClipEvent (enterFrame) {
this.onRollOver = function() {
    this.gotoAndStop("over");
};
this.onRollOut = function() {
    this.gotoAndStop("up");
};
this.onPress = function() {
    this.gotoAndStop("down");
};
this.onReleaseOutside = function() {
    this.gotoAndStop("up");
};
this.onRelease = function() {
    this.gotoAndStop("down");
    whichChoice = this;
    _global.choiceMade = 1;
    counter = 0;
};
if (_global.choiceMade == 1) {
    this.enabled = false;
this._parent.scoreNow = _global.score;
this._parent.scoreOutOf = (this._parent._parent._currentframe)- 1 + ( _global.choiceMade);
if (thisValue == this._parent._parent.Answer && whichChoice == this) {
    myColor = new Color(this);
    myColor.setTint(0,204,0,13);
    this._parent._parent.Answers[0]._alpha = 100;
    this._parent._parent.Answers[0].scaleXY(100);
    this.tick.swapDepths(1000);
    if (counter == 0) {
    _global.score++;
    counter++;
    }
} 
else if (thisValue == this._parent._parent.Answer) {
    myColor = new Color(this);
    myColor.setTint(0,204,0,13);
    this.tick.swapDepths(1000);
}
else if (whichChoice == this) {
    this._parent._parent.Answers[1]._alpha = 100;
    this._parent._parent.Answers[1].scaleXY(100);
    myColor = new Color(this);
    myColor.setTint(255,0,0,13);
    this.cross.swapDepths(1000);
}
else {
    myColor = new Color(this);
    myColor.setTint(255,0,0,13);
    myColor.setTint(255,0,0,13);
    this.cross.swapDepths(1000);
}
}
}

顶部的脚本位于动画片段上，这些按钮包含在名为buttonHolder的内容中，该按钮执行它所说的内容，并在选择答案后补间屏幕上的按钮以显示下一个按钮。

Answer 1

从我所看到的，只要你有choiceMade == 1你就会创造一个新的效果！哪个不行。因为在1秒内以15 fps运行你将有15个补间:(

尝试设置choiceMade = 0或者除了1

之外的其他设置

onClipEvent (enterFrame) 
{
    if (_global.choiceMade == 1) 
    {
        _global.choiceMade = -1;
        var myTweenX:Tween = new Tween(this, "_x", mx.transitions.easing.Back.easeOut, this._x, -349, 0.5, True);
    }
}

Answer 2

如果没有看到其余的代码，很难确切地看到发生了什么。但看起来你永远不会改变choiceMade，它会不断重新创建补间。

onClipEvent (enterFrame) {
if (_global.choiceMade == 1) {
    var myTweenX:Tween = new Tween(this, "_x", mx.transitions.easing.Back.easeOut,      this._x, -349, 0.5, True);
_global.choiceMade = 0;
}
}

Actionscript 2：Tween运行速度极慢

2 个答案: