Question

我有一个包含以下内容的文件：

"BatchID","BatchName","JobName","ScannerID","DateCreated","DailyCounter"
"12713","9001","fst100","09                  ","2/6/2020 6:21:06 AM","1"
"12714","9002","fst100","09                  ","2/6/2020 6:21:42 AM","2"
"12715","9003","fst100","09                  ","2/6/2020 6:21:58 AM","3"
"12716","9004","fst100","09                  ","2/6/2020 6:22:13 AM","4"
"12717","9005","fst100","09                  ","2/6/2020 6:22:30 AM","5"
"12718","9006","fst100","09                  ","2/6/2020 6:24:54 AM","6"
"12719","9007","fst100","09                  ","2/6/2020 6:25:12 AM","7"
"12720","9008","fst100","09                  ","2/6/2020 6:55:11 AM","8"
"12721","9009","fst100","09                  ","2/6/2020 6:55:27 AM","9"

我想比较创建日期的字段，并将相距15分钟或更长时间的行写入文件。

Answer 1

因为：

您的时间戳记字符串采用将其转换为[datetime]（System.DateTime）时的原样格式（除非您的格式列出了 day 而不是第一个月），
您可以直接减去两个[datetime]实例以获得一个[timespan]实例（System.TimeSpan），该实例的.TotalMinutes属性可以查询

解决方案非常简单：

$prevRow = $null
Import-Csv in.csv | ForEach-Object { # Parse the CSV rows into objects and process each
  if ($prevRow -and ([datetime] $_.DateCreated - [datetime] $prevRow.DateCreated).TotalMinutes -gt 15) {
    # Output the previous row and the current row.
    $prevRow; $_
  }
  $prevRow = $_
} # | Export-Csv -NoTypeInformation -Encoding Utf8 out.csv

^{以上将匹配的行打印到屏幕上；删除#以导出到（不同的）CSV文件。}

注意：按照编写的方式，您可以在输出中出现 duplicate 行，即，如果相邻行ABC中A和B以及B和C的间隔都超过15分钟，在这种情况下输出ABBC。

文档链接：

查找时间戳超过给定持续时间的相邻CSV行

1 个答案: