我正在尝试将图像上传到react-native项目中的Firebase存储中,然后在上传完成后返回下载URL。
这是我尝试过的: 编辑:
const uploadImg = async (dispatch, uri, uid, mime = 'image/png') => {
console.log('Starting image upload...');
dispatch({ type: types.UPLOAD_IMG, info: 'Uploading profile image...' });
const uploadUri = Platform.OS === 'ios' ? uri.replace('file://', '') : uri;
return (imageRef = firebase
.storage()
.ref(uid)
.child('profileImg')
.putFile(uploadUri, { contentType: 'image/png' })
.catch((err) => {
uploadImgFail(dispatch, err.message);
}));
};
实施的一部分:
uploadImg(dispatch, img, userCredential.user.uid)
.then((imgRef) => {
const imgUrl = imgRef.getDownloadURL();
console.log('uploaded Image URL: ' + imgUrl)
uploadImgSuccess(dispatch, 'Profile image upload successful...');
// rest of action
}
问题是该函数未返回下载URL,我未处理的承诺被拒绝:“找不到变量:imgUrl”
通过react-native-firebase
实现这一目标有帮助吗?
答案 0 :(得分:3)
您实际上需要从uploadImg
返回一个值。现在它什么也没返回。在return
之前添加imageRef.putFile()
关键字,以返回其链式承诺返回的承诺。