Question

ipv4:
 - address: 192.168.10.1
 - address: 192.168.10.2
 - address: 192.168.10.3

所需的输出：

Col1    Col2        Col3

ABC     Product     Digital
ABC     SubProduct  XF
BCD     Product     Non-Digital
BCD     SubProduct  <White Space>
CDE     Product     Digital
CDE     SubProduct  Null
DEF     Product     Non-Digital
DEF     SubProduct  FR

查询：

Col1    Product         SubProduct

ABC     Digital         XF
DEF     Non-Digital     FR

非常感谢您的帮助

Answer 1

尝试一下：

WITH TAB (Col1, Col2, Col3) AS
(
VALUES
  ('ABC', 'Product', 'Digital')
, ('ABC', 'SubProduct', 'XF')
, ('BCD', 'Product', 'Non-Digital')
, ('BCD', 'SubProduct', ' ')
, ('CDE', 'Product', 'Digital')
, ('CDE', 'SubProduct', Null)
, ('DEF', 'Product', 'Non-Digital')
, ('DEF', 'SubProduct', 'FR')
)
SELECT A.Col1, A.Col3 AS Product, B.Col3 AS SubProduct
FROM TAB A
JOIN TAB B ON B.Col1 = A.Col1 AND B.Col2 = 'SubProduct'
WHERE A.Col2 = 'Product' AND NULLIF(B.Col3, '') IS NOT NULL;

|COL1|PRODUCT    |SUBPRODUCT |
|----|-----------|-----------|
|ABC |Digital    |XF         |
|DEF |Non-Digital|FR         |

dbfiddle example

SQL DB2中具有多个条件的Where子句

1 个答案: